What is the mean,median,mode,range of 0,0,1,3,3,4,5,5,7,7,7,7,7,10,18,50?
vodomira [7]
To find the median, we will list our numbers from least to greatest, and then cross out the smallest number and the biggest number.
0,0,1,3,3,4,5,5,7,7,7,7,7,10,18,50.
0,1,3,3,4,5,5,7,7,7,7,7,10,18.
1,3,3,4,5,5,7,7,7,7,7,10.
3,3,4,5,5,7,7,7,7,7.
3,4,5,5,7,7,7,7.
4,5,5,7,7,7.
5,5,7,7.
5,7.
Since we cannot find a middle number, add the last two numbers up and divide by 2.
5+7 = 12. 12/2=6.
Our median is 6.
The mean is the sum of all numbers divided by how many numbers we have.
0+0+1+3+3+4+5+5+7+7+7+7+7+10+18+50= 132.
We have 16 numbers total.
132/16 = 8.25.
Our mean is 8.25.
The mode is the number that appears the most within the given list.
7 appears the most.
Your mode is 7.
The range is the difference between the largest number and the smallest number.
Our largest number is 50 and our smallest number is 0. The difference of two numbers means to subtract. Subtract 0 from 50.
50-0 = 50.
Your range is 50.
I hope this helps!
The definition of a rhombus is that it's a polygon with four congruent sides. If you split one into two pieces with a diagonal, then yes, it will be two isosceles triangles because two sides are congruent.
Answer:
(a) <u>Sampling distribution
</u>
P(25) = 0,04
P(35) = 0.1 + 0.1 = 0,2
P(42,5) = 0.06 + 0.06 = 0,12
P(45) = 0,25
P(52,5) = 0.15 + 0.15 = 0,3
P(60) = 0,09
(b) E(X) = 45.5 oz
(c) E(X) = μ
Step-by-step explanation:
The variable we want to compute is
For this we need to know all the possible combinations of X1 and X2 and the probability associated with them.
(a) <u>Sampling distribution
</u>
Calculating all the 9 combinations (3 repeated, so we end up with 6 unique combinations):
P(25) = P(X1=25) * P(X2=25) = p25*p25 = 0.2 * 0.2 = 0,04
P(35) = p25*p45+p45*p25 = 0.2*0.5 + 0.5*0.2 = 0.1 + 0.1 = 0,2
P(42,5) = p25*p60 + p60*p25 = 0.2*0.3 + 0.3*0.2 = 0.06 + 0.06 = 0,12
P(45) = p45*p45 = 0.5 * 0.5 = 0,25
P(52,5) = p45*p60 + p60*p45 = 0.5*0.3 + 0.3*0.5 = 0.15 + 0.15 = 0,3
P(60) = p60*p60 = 0.3*0.3 = 0,09
(b) Using the sample distribution, E(X) can be expressed as:
The value of E(X) is 45.5 oz.
(c) The value of μ can be calculated as
We can conclude that E(X)=μ
We could have arrived to this conclusion by applying
Answer:
Hassan will need 12 gallons of gas
Step-by-step explanation:
402 divided by 33.& is 12. he will need 12 gallons of gas
