<span>Let makes the table neater. event D= 100m, even E=800m
(Event D) (Event E)
A won the race (Event A) 30 50
B won the race (Event B) 60 25
A and B tied (Event T) 10 25</span>
B did not win the race today. What length of the race was it more likely to have been? The question is asking in what event did the chance of B did not win(lose + ties) is more likely. Then, you need to determine the chance for B did not win <span>in both race.
Chance of B </span>did not win <span>100-m= 30+10/10=40%
</span>Chance of B did not win 800-m= 50+25/10=75%
The difference would be 75%-40%=35% more likely to lose 800-m race
Answer:
<h2>In the attachment.</h2>
Step-by-step explanation:
Convert the given equation to the form y = mx + b:
<em>add x to both sides</em>
<em>divide both sides by 2</em>
It's a linear function.
We need only two points to plot the graph. Select any two x values, insert into the equation and calculate y values.
for x = 1
for x = -5
Answer:
you may
2x+15+4x+21=90 simplified is 6x+36=90
m<a=33º
m<b=90º
m<c=57º
Step-by-step explanation:
6x+36=90
6x=54
x=9
2(9)+15=33
4(9)+21=57
Answer: = TO A40Y
Step-by-step explanation: ITS RIGHT
Answer:
3y = 8x + 18
for y-intercept let x = 0
3y = 8(0) + 18
3y = 18
y = 6
y-intercept is (0, 6)
THIS IS TRUE
