All categories

3 years ago

How do you find the sum of 74.365 and 9.82?

1 answer:

Citrus2011 [14]3 years ago

8 0

You have to add them, 74.365 + 9.82 = 84.185
You do it just like a normal addition problem but with decimals, the extra 5 at the end doesn’t matter just add another zero at the end of 9.820

You might be interested in

You spend $144 on books and movies you pay $12 per book and $15 per movie you buy three more books than movies how many of each

Zielflug [23.3K]

Answer:

Step-by-step explanation:

23ex xx

8 0

3 years ago

In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70

Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that $P(A) = 0.77$

74% of student are taking an English class

This means that $P(B) = 0.74$

70% of students are taking both

This means that $P(A \cap B) = 0.7$

Find the probability that a randomly selected student is taking a math class or an English class.

This is $P(A \cup B)$ , which is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81$

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

$1 - P(A \cup B) = 1 - 0.81 = 0.19$

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

6 0

3 years ago

Solve: 2.5k+47.4=81.9

belka [17]

Answer:

k=13.8

Step-by-step explanation:

Given function:

2.5k+47.4=81.9
to find k..

Subtract final and middle value:

$81.9-47.4= 34.5$

Divide by 2.5:

$34.5*2.5=13.8$

Therefore, k=13.8..

8 0

3 years ago

A Produce store sold 63 red apples. If the ratio of red apples to green apples sold was 7:2,

valentina_108 [34]

Answer:A Produce store sold 63 red apples. If the ratio of red apples to green apples sold was 7:2,

the combined amount of red and green apples sold is 49:14

Step-by-step explanation:

Hope this helps

6 0

2 years ago

PLEASE HELP

Ksivusya [100]

Answer:

Option (1)

Step-by-step explanation:

Coordinates of the vertices of a quadrilateral WXYZ drawn in the figure are,

W(-1, 4), X(2, 2), Y(0, -1), Z(-3, 1)

Length of a segment having ends as $(x_1, y_1)$ and $(x_2, y_2)$ is represented by,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Length of WX = $\sqrt{(-1-2)^2+(4-2)^2}$

= $\sqrt{9+4}$

= $\sqrt{13}$

Length of XY = $\sqrt{(2-0)^2+(2+1)^2}$

= $\sqrt{13}$

Length of YZ = $\sqrt{(0+3)^2+(-1-1)^2}$

= $\sqrt{13}$

Length of ZW = $\sqrt{(-1+3)^2+(4-1)^2}$

= $\sqrt{13}$

Slope of side WX ( $m_1$ ) = $\frac{y_2-y_1}{x_2-x_1}$

= $\frac{4-2}{-1-2}$

= $-\frac{2}{3}$

Slope of side XY ( $m_2$ ) = $\frac{2+1}{2-0}$

= $\frac{3}{2}$

By the property of perpendicular lines,

$m_1\times m_2=-1$

$(-\frac{2}{3})(\frac{3}{2})=-1$

therefore, WX and XY are perpendicular.

Slope of YZ ( $m_3$ ) = $\frac{-1-1}{0+3}=-\frac{2}{3}$

$m_2\times m_3=(\frac{3}{2})\times (-\frac{2}{3})=-1$

Therefore, XY ⊥ YZ

Similarly, we can prove YZ ⊥ ZW.

Therefore, quadrilateral WXYZ is a SQUARE.

Option (1) will be the answer.

7 0

3 years ago