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Triangles ABC and LBM are similar. We know this because AL and LB have the same length, so that AB is twice as long as either AL or LB. The same goes for MC and BM, and BC. The angle B is the same for both tirangles ABC and LBM, so the side-angle-side postulate tells us the triangles are similar, and in particular that triangle ABC is twice as large as LBM.
All this to say that LM must be half as long as AC, so LM has length (B) 14 cm.
Step 1) Draw a line from point F to point S. A rectangle forms (rectangle FSCW)
Step 2) Find the area of this rectangle. The area is 18 square units because it is 2 units high and 9 units across (9*2 = 18). You can count out the spaces or you can note how we go from x = -4 to x = 5 so subtracting the values gives -4-5 = -9 which has an absolute value of 9.
Step 3) Find the area of triangle FSN. The base is 9 units and the height is 6 units (count out the spaces or subtract y values). So the area is A = b*h/2 = 9*6/2 = 54/2 = 27
Step 4) Add up the area of the rectangle to the area of the triangle: 18+27 = 45
Final Answer: 45 square units
note: another way to find the answer is to find the area of rectangle WABC where point A is at (-4,4) and point B is at (5,4). Then subtract off the triangular areas of AFN and BNS
What is the median of the data?<br>30,29,16,11,16,20,21,12,13,15,15,23,30
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Answer:
16
Step-by-step explanation:
ascending order:11,12,13,15,15,16,16,20,21,23,29,30,30
number of terms =13
median=[(n+1)/2] th term
=[(13+1)/2] th term
=[14/2] th tem
=7th term
=16
Answer:
The range is found by subtracting the lowest number (44) from the highest number (75). 75-44=31 So your range is 31
Step-by-step explanation: