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3 years ago

Help me pleaseeeeeee

Mathematics

1 answer:

Vikki [24]3 years ago

3 0

I think they are equivalent (A) but u should get a second opinion.

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Solve for F:<br> C=5(F-32)/9

puteri [66]

C = 5(F-32)/9 Multiply each side by 9
9C = 5(F-32) Distribute
9C = 5F - 160 Add 160 to each side
9C + 160 = 5F Divide each side by 5
9/5C + 32 = F

5 0

3 years ago

Alla and balla together drink 750ML of water. Of alla drinks 50% more than balla how much does Alla drink

Akimi4 [234]

Answer:

450 ml.

Step-by-step explanation:

Let x be the amount of water drank by Alla and y be the amount of water drank by Balla.

We have been given that Alla and Balla together drink 750 ML of water. We can represent this information as:

$x+y=750...(1)$

We are also told that Alla drinks 50% more than Balla. We can represent this information as:

$x=1.5y...(2)$

From equation (1) we will get,

$y=750-x$

Upon substituting this value in equation (2) we will get,

$x=1.5(750-x)$

Upon distributing 1.5 to right hand side of the equation we will get,

$x=1125-1.5x$

Upon adding 1.5x to both sides of equation we will get,

$x+1.5x=1125-1.5x+1.5x$

$2.5x=1125$

Let us divide both sides of our equation by 2.5.

$\frac{2.5x}{2.5}=\frac{1125}{2.5}$

$x=450$

Therefore, Alla drank 450 ml of water.

8 0

3 years ago

4.5*10^-8/9*10^-9 find the quotient and write it in scientific form

g100num [7]

Answer:

Step-by-step explanation:

4.5*10^-8/ 9*10^-9

1) Reduce the fraction, express 9 as a product of multiplying 4.5*2

4.5*10^-8/4.5*2*10^-9

2) Then notice the common factor of numerator and denominator( 4.5) , get rid of it in both numerator and dnominator

3) 10^-8/ 2*10^-9= 1/2*(10^-8/10^-9)= 0.5* (10^-8/10^-9)

10^-8/10^-9= 10^(-8-(-9))= 10^1=10.

so 0.5*10=5 (it is the answer written in scientific form)

3 0

3 years ago

Can someone help me please

drek231 [11]

Answer:

the answer should be 17

7 0

3 years ago

Evaluate the line integral ?Cx2zds, where C is the line segment from (0,5,2) to (2,7,8).

Leno4ka [110]

Parameterize $C$ by

$\mathbf r(t)=(x(t),y(t),z(t))=(1-t)(0,5,2)+t(2,7,8)=(2t,5+2t,2+6t)$
$\implies\mathrm ds=\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dz}{\mathrm dt}\right)^2}\,\mathrm dt=\sqrt{44}\,\mathrm dt$

So the line integral is equivalent to

$\displaystyle\int_Cx^2z\,\mathrm ds=\sqrt{44}\int_{t=0}^{t=1}(2t)^2(2+6t)\,\mathrm dt=\frac{52\sqrt{11}}3$

5 0

3 years ago