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spayn [35]
3 years ago
5

Penolope earned $50 in may then she earned $60 in june

Mathematics
1 answer:
Anit [1.1K]3 years ago
7 0

Answer:

You are correct, it is 20% increase as:

(60/50) - 1 = 0.2 = 20%

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I needddd helppppp. . . . . .
tankabanditka [31]

Answer:

F. 5:4

Step-by-step explanation:

Solve for a and c to find the ratio of a to c:

  • 2a = 3b
  • a = 3/2(b)
  • 6b = 5c
  • c = 6/5(b)

Now, we can use the value of a and c to find the ratio of a to c:

  • (3/2(b))/(6/5(b))
  • 3b/2 × 5/6b
  • 15b/12b
  • 5/4

F. 5:4 is the correct answer

8 0
4 years ago
Together teammates pedro and ricky got 2685 base hits last season. Pedro had 277 more than ricky. How many hits did each player
Ksju [112]
Let x be the number of base hits Ricky got. With this representation, the number of base hits Pedro got is x + 277. The sum of their number of hits is equal to 2685. The equation that best represent the scenario is,
                                   x + x + 277 = 2685
The value of x is 1204. Therefore, Ricky got 1204 and Pedro got 1481. 
3 0
3 years ago
Segment A’B’ is the result of translating AB by 1 unit to the right and 3 units up
natka813 [3]
In my opinion for me it looks like it could be A or B but if I am wrong then I try :(
5 0
3 years ago
Please take a look at the attachment.
Tanya [424]

Answer:

......

30%..................

3 0
2 years ago
Read 2 more answers
supervisor records the repair cost for 25 randomly selected dryers. A sample mean of $93.36 and standard deviation of $19.95 are
Simora [160]
<h2><u>Answer with explanation:</u></h2>

The confidence interval for population mean (when population standard deviation is unknown) is given by :-

\overline{x}-t^*\dfrac{s}{\sqrt{n}}< \mu

, where n= sample size

\overline{x} = Sample mean

s= sample size

t* = Critical value.

Given : n= 25

Degree of freedom : df=n-1=24

\overline{x}= \$93.36

s=\ $19.95

Significance level for 98% confidence interval : \alpha=1-0.98=0.02

Using t-distribution table ,

Two-tailed critical value for 98% confidence interval :

t^*=t_{\alpha/2,\ df}=t_{0.01,\ 24}=2.4922

⇒ The critical value that should be used in constructing the confidence interval = 2.4922

Then, the 95% confidence interval would be :-

93.36-(2.4922)\dfrac{19.95}{\sqrt{25}}< \mu

=93.36-9.943878< \mu

=93.36-9.943878< \mu

=83.416122< \mu

Hence, the 98% confidence interval for the mean repair cost for the dryers. = 83.4161

4 0
3 years ago
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