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iogann1982 [59]
3 years ago
7

Write a program of while loop 1234 get printed 4231

Computers and Technology
1 answer:
katovenus [111]3 years ago
3 0

Answer:

5221054 i think....

Explanation:

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3 years ago
Why are user manuals important? Select all that apply.
Oksi-84 [34.3K]

Answer:

I. User manuals contain text and images to describe how to use the program features.

II. User manuals explain the commands and syntax of programming languages.

III. User manuals often include chapter on problems and their resolutions.

Explanation:

A user manual can be defined as a clear, detailed and an informative guide drafted by the manufacturer (producer) of a product or service, which is to be given to a customer (end user) so as to help them know and understand how to use the product or service properly.

User manuals are important because they contain the following necessary informations;

I. User manuals contain text and images to describe how to use the program features.

II. User manuals explain the commands and syntax of programming languages.

III. User manuals often include chapter on problems and their resolutions.

Additionally, a user manual contains information on the safety precautions that are to be taken by the end user while using a product or service.

4 0
3 years ago
This function receives first_name and last_name, then prints a formatted string of "Name: last_name, first_name" if both names a
pishuonlain [190]

Answer:

Following are the program in the C++ Programming Language.

//set header file

#include <iostream>

//set namespace

using namespace std;

//define class

class format

{

//set access modifier

public:

//set string type variable

 string res;

//define function

 void names(string first_name, string last_name)

 {  

//set if-else if condition to check following conditions

   if(first_name.length()>0 && last_name.length()>0)

   {

     res="Name: "+last_name+", "+first_name;

   }

   else if(first_name.length()>0 and last_name.length()==0)

   {

     res="Name: "+first_name;

   }

   else if(first_name.length()==0 and last_name.length()==0)

   {

     res="";

   }

 }

//define function to print result

 void out(){

   cout<<res<<endl;

 }

};

//define main method

int main() {

//set objects of the class

 format ob,ob1,ob2;

//call functions through 1st object

 ob.names("John","Morris");

 ob.out();

//call functions through 2nd object

 ob1.names("Jhon","");

 ob1.out();

//call functions through 3rd object

 ob2.names("", "");

 ob2.out();

}

<u>Output</u>:

Name: Morris, John

Name: Jhon

Explanation:

<u>Following are the description of the program</u>:

  • Define class "format" and inside the class we define two void data type function.
  1. Define void data type function "names()" and pass two string data type arguments in its parameter "first_name" and "last_name" then, set the if-else conditional statement to check that if the variable 'first_name' is greater than 0 and 'last_name' is also greater than 0 then, the string "Name" and the following variables added to the variable "res". Then, set else if to check that if the variable 'first_name' is greater than 0 and 'last_name' is equal to 0 then, the string "Name" and the following variable "first_name" added to the variable "res".
  2. Define void data type function "out()" to print the results of the variable "res".
  • Finally, we define main method to pass values and call that functions.
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3 years ago
How to defrost chicken quarter in the microwave?
mash [69]
Use the automatic defrosting feature on your microwave
6 0
4 years ago
Critique and rank four different brands of antivirus software, rating them by price, functionality, and system requirements. Pre
scoundrel [369]

Answer:

Explanation:yes it's true bc you need to order them bye what they are and hope this is right of it isn't I'm truly sorry

5 0
3 years ago
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