You have $15 and admission is $5, so you know have $10 before doing any games. If you wanted to play 12 games, you would need $10.20, which you do not have. But, if you wanted to play 11 games, then you would need $9.35, which is just under $10.
So the maximum amount of games that you could play would be 11 games.
Answer:
0
Step-by-step explanation:
A= (4-1)^3
simplify A to be 3^3
Which gives us 27
B=(2*3)^2-9
simplify B
first multiply the 2 numbers in paranthesis which gives us 6. raise it to the power of 2 which is 39 and then subtract 9. Gives us 27.
C=15^3*4-12
Simplify the exponent first. 3*4 gives us 12 and 12-12 equals 0. Anything raised to the power of 0=1
If A-B^C is the equation we can write 27-27 raised to the power of 1 which is 0
I’m pretty sure This rounds to 900
Answer:
The answer is between first option and last option.
Step-by-step explanation:
That my Contributions to this questions
<em>V</em>≈301.59
I think this is the answer.
Hope this helps!