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charle [14.2K]
3 years ago
5

Cavin drank 3/4 of a liter of orange juice from a container, which was 3/8 of the orange juice that was originally in the contai

ner. How much orange juice was originally in the container?
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer:

2 liters

Step-by-step explanation:

Let

x ----> amount of the orange juice originally in the container in liters

we know that

The amount of the orange juice originally in the container multiplied by 3/8 must be equal to 3/4 of a liter of orange juice

so

The linear equation that represent this situation is

\frac{3}{8}x=\frac{3}{4}

solve for x

x=24/12=2\ L

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Leviafan [203]

no because she turned it only 90 degrees not 180.

180 would be a mirror reflection

6 0
3 years ago
A clown bought 6 bags of round balloons with 24 balloons in each bag.The clown also bought 3 bags of long balloons with 36 ballo
Ierofanga [76]
6 bags × 24 balloons = the amount of round balloons
6× 24 = 144
3 bags × 36 balloons = the amount of long balloons
3 ×36=108

108 long balloons - 144 round balloons = number of more long balloons that round ones
108-144=-36
He has -36 more long balloons that round ones
Or 36 more round balloons that long ones
7 0
3 years ago
What is the following quotient?
almond37 [142]

Answer:

B)  \sqrt{30}  - 3 \sqrt{2}  +  \sqrt{55}  -  \sqrt{33}  \div 2

Step-by-step explanation:

Step 1: First we have to get rid off the roots in the denominator.

To do that, we have to multiply the numerator and the denominator by the conjugate of √5 + √3.

The conjugate of √5 + √3 is √5 - √3.

Now multiply given expression with √5 - √3

(√6 + √11)     (√5 - √3)

------------- x   -----------

(√5 + √3)        (√5 - √3)

Step 2: Multiply the numerators and the denominators.

√6√5 - √6√3 +√11√5 -√11√3

------------------------------------------

(√5)^2 - (√3)^2

Now let's simplify to get the answer.

√30-√18 +√55 - √33

-----------------------------

5 - 3

= √30 -3√2 +√55                                     [√18 = √9√2 = 3√2]

--------------------------

2      

The answer is  \sqrt{30}  - 3 \sqrt{2}  +  \sqrt{55}  -  \sqrt{33}  \div 2


Thank you.

4 0
3 years ago
Read 2 more answers
Find the value of questions​
Zolol [24]

Answer:

The simplified expression is:

\frac{3^9y}{2\times \:81}=\frac{243y}{2}

Step-by-step explanation:

Given the expression

\frac{3^9\times \:y}{2\times 81}

solving the expression

\frac{3^9\times \:y}{2\times 81}=\frac{3^9y}{162}

        =\frac{3^9y}{3^4\times \:2}                ∵    162=3^4\times \:2      

        =\frac{3^5y}{2}                   ∵   \mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}

       =\frac{243y}{2}                  ∵    3^5=243

Therefore, the simplified expression is:

\frac{3^9y}{2\times \:81}=\frac{243y}{2}

6 0
3 years ago
Tyler is offered to choose between three boxes that look identical. The first box contains 1 red pills and 19 blue pills, the se
Dafna1 [17]

Answer:

A) 0.15

B) 0.36

Step-by-step explanation:

First Box consist 1 red pills and 19 blue pills

second box consist 6 red pills and 14 blue pills

Third box consist 2 red pills and 18 blue pills

a) Prob ( randomly chosen pill is red) = \frac{1}{3} \times \frac{1}{20} + \frac{1}{3} \times \frac{6}{20} + \frac{1}{3} \times \frac{2}{20}

\frac{1}{60} (1+6+2) = 0.15

b)Prob ( 1 reds and 10 blue pilss) =\frac{1}{3} \frac{^1C_1\times ^{19}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^6C_1\times ^{14}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^2C_1\times ^{18}C_{10}}{^{20}C_{11}}

= \frac{1}{3} 1.106 = 0.368

7 0
3 years ago
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