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adoni [48]
4 years ago
14

Help me plz I am confused

Mathematics
2 answers:
lions [1.4K]4 years ago
5 0

Answer:

> Means "is greater than"

< means "is less than"

≠ means "is not equal to"

SVEN [57.7K]4 years ago
4 0

Answer:

> means greater than

< means less than and the last one is "not equal to"

Hope this helps!

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Rewrite 16/16 as a whole number
son4ous [18]
The answer to your question is one
4 0
3 years ago
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Mike and Dena are painting a fence. if Mike has done 1/3 of the job and Dena has done 2/7 of the job, what fraction of the job i
ludmilkaskok [199]

Answer:

8/21

Step-by-step explanation:

The total job is 1

Mike has done 1/3    and Dena has done 2/7 of the job   We still need to do x of the job to complete it

1/3 + 2/7+ x  = 1

We need to get a common denominator 3*7 = 21

Multiply each side by 21

21(1/3 + 2/7+ x)  = 1*21

21(1/3) + 21*(2/7)+ 21x  = 21

7+ 3*2 +21x =21

7+6+21x = 21

13+21x = 21

Subtract 13 from each side

13-13+21x=21-13

21x = 8

Divide each side by 21

21x/21 = 8/21

x = 8/21

We need to complete 8/21 of the job

3 0
3 years ago
Mya returned 14 books to the library. She
ehidna [41]

Answer:

27 books

Step-by-step explanation:

14+13=27

6 0
3 years ago
Rotate the vector (0,2) 270 degrees counterclockwise about the origin
SashulF [63]
<h3>Answer:  (2,0)</h3>

Explanation:

The vector (0,2) points directly north and the length of this vector is 2 units. It's the distance from (0,0) to (0,2).

When rotating 270 degrees counterclockwise, we'll turn to the left or westward direction (90 degrees so far) then at some point aim directly south (180 degrees so far) and finally ultimately end up pointing directly east (after getting to 270). So that's how we go from (0,2) to (2,0).

If you were to go clockwise, then everything flips and you'll ultimately end up pointing directly west. The length of the vector stays the same the whole time.

3 0
3 years ago
Please help
Murrr4er [49]
<h3>You have the correct answer. It is choice B. Nice work.</h3>

K is the midpoint, so \overline{IK} \cong \overline{GK} and \overline{JK} \cong \overline{HK}, and along with the congruent vertical angles (\angle GKH \cong \angle IKJ and \angle GKJ \cong \angle IKH), you would use the SAS (side angle side) congruence theorem to prove the inner pairs of triangles to be congruent.

So, \triangle HKG \cong \triangle JKI (top and bottom triangles) and \triangle GKJ \cong \triangle IKH (left and right triangles).

Then through CPCTC, we can show the corresponding pieces are congruent leading to \overline{GH} \cong \overline{JI} and \overline{GJ} \cong \overline{HI} showing the opposite sides of the quadrilateral are congruent. Therefore we do have a parallelogram and enough information to prove it as such.

Side note: CPCTC stands for "corresponding parts of congruent triangles are congruent".

3 0
4 years ago
Read 2 more answers
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