Answer:
The jar has 32 dimes and 18 quarters
Step-by-step explanation:
<u>To solve this problem we can create a system of linear equations in terms of two-variables (say </u>
<u> and </u>
<u>) and solve it.</u> To begin let us analyze the problem further. We know that the values of each coin type are:
Dimes (
) = $0.10
Quarters(
) = $0.25
Total Value = $7.70
Total Coins = 50
Now let us set up our system of equations as:
Eqn.(1)
Eqn.(2)
Lets take Eqn.(2) and rerrange it to solve for
as:
Eqn.(3)
Now lets plug this, in Eqn.(1) so we get the value of
as:


Plugging in
back in Eqn.(3) we finally have:

Thus we conclude that in the jar the coins are:
Dimes (
) 
Quarters(
) 
Answer:
1
Step-by-step explanation:
First play=9
Second play=5
Third pla=7
Fourth play=4
9-5-7+4
=1
Answer:
57
Step-by-step explanation:
Subtract 38 from 95 to get 57
Okay, lets see here. So since we know that 26 is six less than the actual answer, we'll add 6 to 26 which gives us 32. Then we'll do 32 divided by 4, which is 8.
Answer:
3x
Step-by-step explanation:
2x + x
3x
Answer: 3x