Question

A metal alloy weighing 5kg and containing 22% iron melted and mixed with 12 kg of a different alloy which contains 90% iron. What percent of the resulting alloy is iron?

Answer 1

Answer:

70%

Step-by-step explanation:

Given the weight of the first alloy as 5kg(22% iron) and the second as 12kg(90% iron:

#First, we find the weight in kgs of the iron in both alloys:

$I_a=0.22\times 5.0kg\\\\\\=1.1kg\\\\I_b=0.90\times 12kg\\\\=10.8kg\\\\I_a+I_b=1.1+10.8=11.9kg$

Hence, the weight of iron in the resulting alloy is 11.9kg.

#From the given info,the total mass of the alloy is 5+12=17kg

Therefore, the % of iron is calculated as :

$\% Iron=I_{a+b}/T_m\\\\=\frac{11.9}{17}\times 100\%\\\\=70\%$

Hence, 70% of the resulting alloy is iron.