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oee [108]
3 years ago
10

A trapezoid has two bases that measure 11 cm and 8 cm. The height of the figure is 5 cm. What is the area of the trapezoid?A tra

pezoid has two bases that measure 11 cm and 8 cm. The height of the figure is 5 cm. What is the area of the trapezoid?
Mathematics
1 answer:
Law Incorporation [45]3 years ago
4 0

Answer:

47.5

Step-by-step explanation:

A= h·(\frac{b1+b2}{2})

So, 11cm+8cm=19cm

19cm÷2=9.5cm

9.5cm×5cm=47.5cm

Therefore your answer is 47.5cm

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3 years ago
Hi, teacher I was absent these days and I didn’t understand anything about this lesson and I need help this is not count as a te
motikmotik

Given:

There are given that the cos function:

cos210^{\circ}=-\frac{\sqrt{3}}{2}

Explanation:

To find the value, first, we need to use the half-angle formula:

So,

From the half-angle formula:

cos(\frac{\theta}{2})=\pm\sqrt{\frac{1+cos\theta}{2}}

Then,

Since 105 degrees is the 2nd quadrant so cosine is negative

Then,

By the formula:

\begin{gathered} cos(105^{\circ})=cos(\frac{210^{\circ}}{2}) \\ =-\sqrt{\frac{1+cos(210)}{2}} \end{gathered}

Then,

Put the value of cos210 degrees into the above function:

So,

\begin{gathered} cos(105^{\circ})=-\sqrt{\frac{1+cos(210)}{2}} \\ cos(105^{\operatorname{\circ}})=-\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}} \\ cos(105^{\circ})=-\sqrt{\frac{2-\sqrt{3}}{4}} \\ cos(105^{\circ})=-\frac{\sqrt{2-\sqrt{3}}}{2} \end{gathered}

Final answer:

Hence, the value of the cos(105) is shown below:

cos(105^{\operatorname{\circ}})=-\frac{\sqrt{2-\sqrt{3}}}{2}

4 0
1 year ago
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3 years ago
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Answer:

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Step-by-step explanation:

Since the 3 dozen cookies she baked was 1/4th the amount in total, all you have to do to find the total amount is multiply the fraction of the cookies 3 dozen (36) by 4.

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6 0
3 years ago
How do I solve this problem??
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3 years ago
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