Step-by-step explanation:
EF is a segment so it's a line with the end points as E and F. Line RS bisects(cuts in half) line EF. Then where the two lines meet is where A is.
Hope this helped.
Let's pick two points on the line, the
y-intercept, and the
x-intercept. These are the points at which x=0, and y=0.
When x=0:

So one point is
(0,6)When y=0:

So another point is
(10,0)
So mark the points
(0,6) and
(10,0) on a pair of axes, and draw a straight line between them, and past them to infinity. This is a graphing of the line y=-3/5 x + 6
Answer:
90°
Step-by-step explanation:
Through point O draw a ray on left side of O which is || to AB & CD and take any point P on it.
Therefore,
∠ABO + ∠BOP = 180° (by interior angle Postulate)
118° + ∠BOP = 180°
∠BOP = 180° - 118°
∠BOP = 62°.... (1)
Since, ∠BOP + ∠POD = ∠BOD
Therefore, 62° + ∠POD = 152°
∠POD = 152° - 62°
∠POD = 90°.....(2)
∠POD + ∠ODC = 180° (by interior angle Postulate)
90° + ∠ODC = 180°
∠ODC = 180° - 90°

Answer:
0.005323
Step-by-step explanation:
Use the algorithm method
A. -8 Because there’s a negative in -4ac