Question

At the fair Craig has 232 ride tickets each ride on the Ferris wheel costs 6 tickets after riding the Ferris wheel as many times as possible how many tickets will Craig have left

Answer 1

Answer:

Criag have left with 4 tickets .

Step-by-step explanation:

Criag have total no. of ride tickets = 232

Each ride of the Feris Wheel cost no. of tickets = 6

6 tickets are required to cover each ride of Feris wheel

So, 232 tickets are required to cover no. of rides of Feris wheel = $\frac{232}{6}$

232 tickets are required to cover no. of rides of Feris wheel = $\frac{232}{6}=38.66$

1 ride of Ferris wheel cost no.of tickets = 6

38 rides of Ferris wheel cost no.of tickets =$6 \times 38 =228$

So, Tickets left = 232-228=4

Hence Criag have left with 4 tickets .