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lyudmila [28]
3 years ago
8

Find the perimeter of a regular heptagon with consecutive vertices at "A" (-2,-5) and "B" (1,-9)

Mathematics
1 answer:
weqwewe [10]3 years ago
7 0

Answer:

Perimeter is 35 units.

Step-by-step explanation:

A heptagon has 7 equal sides.

Given the length of two consecutive vertices, A(-2-5) and B(1,-9).

We can find the length of AB and multiply by 7.

Recall the distance formula;

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The length of AB is

|AB|=\sqrt{(-2-1)^2+(-5--9)^2}

|AB|=\sqrt{(-3)^2+(4)^2}

\Rightarrow |AB|=\sqrt{9+16}

\Rightarrow |AB|=\sqrt{25}

\Rightarrow |AB|=5\:units

Therefore the perimeter is 7\times 5=35\:units.

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