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3 years ago

What is 0.345 in standard form

Mathematics

2 answers:

BARSIC [14]3 years ago

7 0

Answer:

Step-by-step explanation:

The ans is 345/1000

Vikentia [17]3 years ago

4 0

Answer: 3.45x10⁻1

Step-by-step explanation:

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There are twelve people on the jury there were 4more man than women how many man were <br>there/

irina1246 [14]

$x-the \ number \ of \ women \\ x+4 -the \ number \ of \ men \\\\ x+x+4=12 \\\\ 2x+4=12 \\\\ 2x=12-4 \\\\ 2x=8 \\\\ \boxed{x=\frac{8}{2}=4 \ women} \\\\ x+4= \\\\ = 4+4\to\boxed{8 \ men}$

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3 years ago

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-1/2 minus negative 5/9 equal what

Andrej [43]

I think it’s -19/18 hope it helped

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3 years ago

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Let f be defined as shown.<br> What is f^-1(8)?

Gnoma [55]

Answer:

From the picture when the input of f(x) is 6 the output is 8

So it's just the reverse f^-1(8) when the input is 8 the output is 6

So f^-1(8) = 6

Hope this helps you

4 0

4 years ago

Approximate the sum of the convergent infinite series the least usingnumber of terms so that the error is less than .0001. What

____ [38]

Solution :

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ $a_n= \frac{(-1)^n}{n ! 2^n} \ \ \ \ \ a_{n+1}= \frac{(-1)^{n+1}}{(n+1) ! 2^{n+1}}$

Error = $|a_{n+1}|$

Error ≤ 0.0001

$|\frac{(-1)^{n+1}}{(n+1)!2^{n+1}}| \leq 0.0001$

$|\frac{1}{(n+1)!2^{n+1}}| \leq 10^{-4}$

$(n+1)! 2^{n+1} \geq 10000$

Now try, n ≥ 5

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ = $\sum_{n=1 }^{5 } \frac{(-1)^n}{n ! 2^n}$ (with error 0.0001)

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ = $\frac{-1}{1!2}+\frac{1}{2!2^2}-\frac{1}{3! 2^3}+\frac{1}{4! 2^4}-\frac{1}{5! 2^5}$

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ = 0.6065104

3 0

3 years ago

Consider the following least squares specification between test scores and the student - teacher ratio: TestScore = 557.8 + 36.4

GenaCL600 [577]

Answer:

$Test score_i= 557.8 +36.42 Income$

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

$Test score_f = 557.8 + (36.42* 1.01 Income)= 557.8 +36.7842 Income$

And the net increase can be founded like this:

$Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642$

So then the net increase would be:

C. 0.36 points

Step-by-step explanation:

For this case we have the following linear relationship obtained from least squares between test scores and the student-teacher ratio:

$Test score_i= 557.8 +36.42 Income$

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

$Test score_f = 557.8 + (36.42* 1.01 Income)= 557.8 +36.7842 Income$

And the net increase can be founded like this:

$Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642$

So then the net increase would be:

C. 0.36 points

5 0

3 years ago

What is 0.345 in standard form​

What is 0.345 in standard form