H²+10h+21 = 0
h²+3h+7h+21 = 0
h(h+3)+7(h+3) = 0
(h+3)(h+7) = 0
h+3=0
h = -3
h+7=0
h=-7
(base area)*h
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Answer:
x = <u>16</u> units
Step-by-step explanation:
∆ABC is a 45-45-90 triangle, and ∆BCD is a 30-60-90 triangle.
If side opposite of 90° [∆] = x, side opposite of 45° [∆] = x / √2 = x √ 2 / 2.
Given side AC is opposite of 90° [∆ABC] = 32 √ 2, side opposite of 45° [∆ABC] = 32 √ 2 / √ 2 = 32 which is AB or BC.
Since side BC is part of BCD.
Side opposite of 90° [∆BCD] = BC = 32.
Since x is opposite of 30° [∆BCD].
x = Side opposite of 90° [∆BCD] / 2 = 32 / 2 = 16.
So what will it be a percentage of? it will be the percentage of the original recruits, of the original 150.
for this, we need to divide the number of recruits that left over all recruits, and multiply by 100%:

so the number of trainees decreased by 20 %
Answer:
9 tenths is the value
Step-by-step explanation: