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3 years ago

LET'S GOOOOOOOOO!!!!!!!!!!!

Mathematics

2 answers:

Ulleksa [173]3 years ago

7 0

Answer:

lets goooooooooooooooooooooooooooooooooooooooooooo0poooooooooooooooo

Step-by-step explanation:

Sloan [31]3 years ago

4 0

Answer: YAYYYY

Step-by-step explanation:

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Select the correct answer.

Orlov [11]

Answer: C 28.47° latitude and -7.35° longitude

Step-by-step explanation:

6 0

2 years ago

80 POINTS!!!!!!

Lera25 [3.4K]

Plz dont be mean to me i just wanna understand and also its the blue line for answer 1

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3 years ago

HELPPPPPPPPPPPPPP PLZZZZZZZZZZZ clock arithmetic Will mark brainiest .

GarryVolchara [31]

Answer:

a) 29

b) 0

c) 7

d) 3/8

Step-by-step explanation:

Whenever you're facing a clock maths problem, the solution always have to be < to the number of hours in the given clock. If it's > the number of hours of the given clock, you subtract the number of hours until you get a result <= the number of clock hours.

If the result is negative, you add the clock hours.

a) 21 - 33 = -12 , so -12 + 41 = 29

b) 13 * 4 = 52, then do 52 - 52 = 0, since answer has to be < 52.

c) 11+19 = 30, 30 - 23 = 7

d) 3/8 = 3/8, since 3/8 <= 15, you're also fine.

7 0

3 years ago

Please help me solve this problem

sergiy2304 [10]

Answer:

-2/3x+6

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f

Ann [662]

Answer:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The estimated population proportion for this case is:

$\hat p = \frac{350}{500}=0.7$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

7 0

3 years ago

LET'S GOOOOOOOOO!!!!!!!!!!!​

LET'S GOOOOOOOOO!!!!!!!!!!!