All categories

3 years ago

Please help! Thanks!

Mathematics

1 answer:

Ede4ka [16]3 years ago

5 0

-9(6m-3)+6(1+4m)
=54m+27+6(1+4m)
=54m+27+6+24m
= -30m+33

You might be interested in

The point (-6, 4) is reflected over the x-axis. Find the point of reflection.

MrRa [10]

Answer:

-6, -4

Step-by-step explanation:

5 0

2 years ago

I inserted a picture please help!!!

igomit [66]

The answer is: [D]: " C = 2 π r " .
___________________________________________

4 0

4 years ago

Two right rectangular prism‘s are shown below

Katena32 [7]

Answer:

need a image to answer this

7 0

3 years ago

Help me on this please

Andre45 [30]

First you have to find the area of the rectangle.
A=Lw
A=91(68)
A=6,188 m
Next you have to find the area of the semi- circles.
A of circle= radius to the second power times pi
A=68x68
A= 4,624
Multiply the area of the semi- circles by 2 since there are two of them. That will give you 9,248 m. Add 9,248 with 6,188 and that will give you your final answer which is 15,436 m.

7 0

3 years ago

Read 2 more answers

According to a research center, 16% of all merchandise sold in a particular country gets returned. A department store in a certa

Mamont248 [21]

Answer:

a) point estimate of the proportion of items returned for the population of sales transactions at the store in the given city

Point estimate = 0.3

b) The 95% confidence interval for the proportion of returns at the store in the given city

( 0.19958,0.40042)

Step-by-step explanation:

Given the Population proportion 'P'= 16% = 0.16

Given data a department store in a certain city sampled 80 items sold in January and found that 24 of the items were returned

The sample proportion $p = \frac{x}{n}$

here x =24 and n = 80

The sample proportion $p = \frac{x}{n} = \frac{24}{80} = 0.3$

a) Point estimate:-

A point estimate of the true proportion P

Point estimate = $p = \frac{x}{n}$

point estimate of the proportion of items returned for the population of sales transactions at the store in the given city

$p = \frac{x}{n} = \frac{24}{80} = 0.3$

b) The 95% confidence interval for the proportion

The 95% confidence interval for the proportion of returns at the store in the given city

$(p - z_{\alpha } \sqrt{\frac{p(1-p)}{n} } , p + z_{\alpha }\sqrt{\frac{p(1-p)}{n} } )$

substitute all values we get ,

$(0.3 - 1.96 \sqrt{\frac{0.3(1-0.3)}{80} } , 0.3 + 1.96\sqrt{\frac{0.3(1-0.3)}{80} } )$

on simplification, we get

(0.3-0.10042 ,0.3+0.10042)

( 0.19958,0.40042)

Conclusion:-

a) point estimate of the proportion of items returned for the population of sales transactions at the store in the given city

Point estimate = 0.3

b) The 95% confidence interval for the proportion of returns at the store in the given city

( 0.19958,0.40042)

5 0

4 years ago