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eimsori [14]
3 years ago
13

Which of the following is a solution of x2 + 8x = −32?

Mathematics
1 answer:
iren2701 [21]3 years ago
3 0

Answer:

-4±4i is the solution of x²+8x  = -32.

Step-by-step explanation:

We have given a quadratic equation.

x²+8x  = -32

x²+8x+32  = 0

We have to find the value of x.

We use quadratic formula to solve above equation.

ax²+bx+c  = 0 is general quadratic equation.

Comparing given equation to general quadratic equation, we have

a  = 1 , b  = 8 and c  = 32

x  = (-b±√b²-4ac ) / 2a is quadratic formula to solve equation.

putting given values in above formula, we have

x  = (-8±√(8)²-4(1)(32) ) / 2(1)

x  = (-8±√64-128) / 2

x  = (-8±√-64) / 2

x  = (-8±8i) / 2

x  = 2(-4±4i) / 2

x  = -4±4i is the solution of x²+8x  = -32.

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Answer:

  a) ∠DAE = 33°; ∠ABD = 57°

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Step-by-step explanation:

The diagonals of a rhombus meet at right angles. Each bisects the corner angles at its ends. Adjacent angles are supplementary, opposite angles are congruent, and each diagonal creates two isosceles triangles.

a) ∠DAE = 90° - ∠ADE = 90° -57°

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b) ∠CEB = 90° . . . . . the diagonals meet at right angles

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c) ∠ABE = 44°/2

  ∠ABE = 22°

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d) ∠ADE = 90° -(1/2)∠DAB = 90° -150°/2

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