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kakasveta [241]
3 years ago
15

What's the answer to this question ?

Mathematics
1 answer:
Korvikt [17]3 years ago
4 0
I think the answer is B
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Please help, very confused
miss Akunina [59]

Answer:

1.

-3x + 8y = -5

6x + 2y = -8

Set the equations to a common variable.

-3x + 8y = -5 → 8y = 3x - 5 → y = 3/8x - 5/8

6x + 2y = -8 → 2y = -6x - 8 → y = -3x - 4

Set the equations equal to each other.

3/8x - 5/8 = -3x - 4

Combine like terms.

3x + 3/8x = -4 + 5/8

3.375x = -3.375

Divide by 3.375

x = -1

Plug x back in to find y.

-3x + 8y = -5

-3(-1) + 8y = -5

3 + 8y = -5

8y = -8

y = -1

answer: (-1, -1)

2.

3x + 2y = -16

-3x - 8y = 46

Set the equations to a common variable.

3x + 2y = -16 → 2y = -3x - 16 → y = -3/2x - 8

-3x - 8y = 46 → -8y = 3x + 46 → y = -3/8x - 23/4

Set the equations equal to each other.

-3/2x - 8 = -3/8x - 23/4

Combine like terms.

-9/8x = 9/4

or

-1.125x = 2.25

Divide by -1.125

x = -2

Plug x back in to find y.

3(-2) + 2y = -16

-6 + 2y = -16

2y = -10

y = -5

answer: (-2, -5)

6 0
3 years ago
Read 2 more answers
I need help with this please
Harlamova29_29 [7]
-12y+14-9y=14
-21y=0
y=0, x=7
3 0
3 years ago
Select the ordered pairs that are solutions to the inequality 2x-3y greater than or equal to 12
Dima020 [189]
Just rank every pair of numbers for example:
The first one is: 1,-3.
2•1-3•-3>12
2+9>12
11>12
That's Incorrect. The first pair of numbers doesn't match the inequality.
Now do the same thing to all the other pairs of numbers.
3 0
3 years ago
Read 2 more answers
Using multiplication property of equality solve x/2=6
weeeeeb [17]
\frac{x}{2} = 6
\frac{x}{2} (2) = 6(2)
x=12
5 0
3 years ago
Read 2 more answers
Pls help me!!!!solve this question
nasty-shy [4]
(11k^4 - 4m) + (-2k^4 - 15m)
Add -2k^4 to 11k^4. This would be the same as subtracting 2k^4 from 11k^4
9k^4 - 4m - 15m
Add -15m to -4m. This would be the same as subtracting 15m from -4m
Final Answer: 9k^4 - 19m

Word Form: Nine times the variable k to the forth power minus nineteen times the variable m.
3 0
3 years ago
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