Ask question

Ask question

All categories

3 years ago

15

The equation models the (h) height in centimeters after (t) seconds of a weight ttached to the end of a spring that has been str

etched and released.
h=7cos(pi/3 t) Solve for t.

1 answer:

Elena L [17]3 years ago

6 0

Answer:

t = 3 arc cos(h/7)/π

Step-by-step explanation:

The equation h=7cos(pi/3 t) models the (h) height in centimeters after (t) seconds of a weight attached to the end of a spring that has been stretched and released. To solve the equation for t we will solve the equation step by step:

h=7cos(pi/3 t)

Step 1)

Divide both sides by 7

h/7 = 7cos(pi/3 t)/7

Now the equation becomes h/7=cos(pi/3 t)

Step 2)

h/7=cos(pi/3 t)

Now apply inverse cosine function:

arc cos (h/7) = pi/3 t

Step 3)

t = 3 arc cos(h/7)/pi

Thus t = 3 arc cos(h/7)/pi ....

You might be interested in

Find the value of 2.<br> 78°<br> 1200<br> 15°<br> B

andrew11 [14]

I tried but see if this helps you In algebra, it is easy to find the third value when two values are given. Generally, the algebraic expression should be any one of the forms such as addition, subtraction, multiplication and division. To find the value of x, bring the variable to the left side and bring all the remaining values to the right side.

5 0

2 years ago

A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is

scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=360000$ represent the mean for the downtown restaurant

$\bar X_{2}=340000$ represent the mean for the freeway restaurant

$s_{1}=50000$ represent the sample standard deviation for downtown

$s_{2}=40000$ represent the sample standard deviation for the freeway

$n_{1}=36$ sample size for the downtown restaurant

$n_{2}=36$ sample size for the freeway restaurant

t would represent the statistic (variable of interest)

$\alpha=0.05$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis: $\mu_{1}\leq \mu_{2}$

Alternative hypothesis: $\mu_{1} > \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level $\alpha=0.05$ and $\alpha/2=0.025$ we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is $t_{1-\alpha/2}=1.66$

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874$

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

$p_v =P(t_{70}>1.874)=0.033$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.

The best option would be:

Yes, since the test statistic value is greater than the critical value.

5 0

2 years ago

Y is directly related to x and y is 81 when x is 27 the constant of.variation is

suter [353]

Answer:

The constant of variation is 3

Step-by-step explanation:

Given.

$y=81$

$x=27$

And y is directly related to x

$y$ ∝ $x$

Here k is constant of variation

$y=kx$

$k=\frac{y}{x}$ --------------(1)

Put the $y$ and $x$ value in equation 1.

$k=\frac{81}{27}$

$k=3$

So, the constant of variation is 3.

6 0

3 years ago

Worth 10 points pls help

Olenka [21]

What subject is this

3 0

2 years ago

Find the mean of the data set: 9 4 7 3 10 9

almond37 [142]

To find the mean, add up at the numbers and divide by the number of numbers in the set (6)

9 + 4 + 7 + 3 + 10 + 9 =
9 + 11 + 12 + 10
20 + 22
42

42 / 6 = 7

the mean is 7.

6 0

3 years ago

Read 2 more answers