8 ..................................
Answer:
∠ EBF = 40°
Step-by-step explanation:
Given BF bisects ∠ CBE , then
∠ CBF = ∠EBF , substitute values
7x - 2 = 6x + 4 ( subtract 6x from both sides )
x - 2 = 4 ( add 2 to both sides )
x = 6
Thus
∠ EBF = 6x + 4 = 6(6) + 4 = 36 + 4 = 40°
If you unroll the fence, you find it has a length equal to the circumference of a circle of radius 10 m and an average height of 3 m. Its two-sided area will be
... A = 2·(3 m)·(2π·(10 m)) = 120π m²
Then the amount of paint required is
... (120π m²) × (1L)/(100 m²) = 1.2π L ≈ 3.77 L
Answer:
CV for statistics exam = 15%
CV for calculus exam = 19%
Since the CV for calculus exam is higher, it has a greater spread relative to the mean than the statistics exam.
Step-by-step explanation:
To find coefficient variation we use the formula:
CV = (SD/mean) * 100
CV for the statistics exam:
where; SD= 5
mean= 75
CV = ( 5/75) *100
= 0.15 or 15%
CV for calculus exam
SD = 11
Mean= 58
CV= (11 /58) * 100
= 0.19 or 19%
Answer:
Step-by-step explanation:
The negative out front only tells us which way the parabola will open. That means that the first one will open upside down, since it's got a negative out front. The value of the number that serves as the leading coefficient (the number stuck to the x-squared) determines how steep or wide-open the parabola's shape is. The leading coefficient in the first one is a 1, so it opens up exactly as wide as its parent graph does. The leading coefficient in the second one, a 2, means that the parabola will be skinnier or narrower than its parent. If the leading coefficient is greater than 1, the parabola will be narrower than its parent; if the leading coefficient is greater than 0 but less than 1, the parabola will open wider than its parent.
