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3 years ago

there are 4 trucks for every 5 cars in a parking lot. how many trucks and cars could be in a parking lot?

Mathematics

2 answers:

hjlf3 years ago

7 0

Answer:

there could be 8 trucks to 10 cars

16 trucks to 20 cars

or just continuously multiply by 2

Sedaia [141]3 years ago

4 0

Answer:

there could be 8 trucks to 10 cars

16 trucks to 20 cars

or just continuously multiply by 2

Step-by-step explanation:

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At Sundae King, 4 of the last 6 sundaes sold had nuts. Considering this data, how many of

nordsb [41]

Answer:

Step-by-step explanation:

4/6=2/3

18(2/3)=12

5 0

3 years ago

Read 2 more answers

A group of college students were asked about their TV watching habits. Of those surveyed, 30 students watch The Walking Dead, 24

Usimov [2.4K]

Answer: 44 students

Step-by-step explanation:

Let Walking dead be denoted as W

Let Blacklist be denoted as B

Let Game of thrones be denoted as G

Total number of students that watch W = 30

W&G&B = 7

W&B only = 13-7 = 6

W&G only = 10-7 = 3

To get the number of people that watch W ONLY, we subtract those that watch W&B only (6), W&G only(3) and W&B&G(7) from 30. Hence,

W Only = 30 - 6- 3 - 7= 14 (14 students watch Walking dead only)

Total number of students that watch B =24

B&G&W = 7

B&W only = 13-7 = 6

B&G only = 16 - 7 = 9

Hence, those that watch B only = 24-6-9-7= 2 students.

Total number of students that watch G = 22

G&W&B = 7

G&B only = 9

G&W only = 3

Hence those that watch G only = 22-9-3-7 = 3 students.

Hence number of students that watch at least one show = W only + B only + G only + W&B only + W&G only + B&G only + W&B&G.

= 14+2+3+6+3+9+7 = 44 students.

3 0

3 years ago

How much fabric is needed to make curtains for a 5foot tall 3 foot wide window?

SpyIntel [72]

Area = 5(3) = 15 feet

3 0

3 years ago

Which input value produces the same output value for the two functions on the graph?

DiKsa [7]

Answer:

The input value is 3/4

Step-by-step explanation:

we know that

The input value that produces the same output value for the two linear functions, is the intersection point both graphs

we have

$f(x)=-3x+1$ ---> equation A

$g(x)=x-2$ ---> equation B

Equate equation A and equation B

$x-2=-3x+1$

solve for x

$3x+x=1+2$

$4x=3$

$x=\frac{3}{4}$

therefore

The input value is 3/4

5 0

3 years ago

Use calculus to find the absolute maximum and minimum values of the function. (round all answers to three decimal places.) f(x)

Allisa [31]

Part A:

Given the function $f(x)=x+2\cos(x)$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow1-2\sin{x}=0 \\ \\ \Rightarrow2\sin{x}=1 \\ \\ \Rightarrow\sin{x}= \frac{1}{2} \\ \\ \Rightarrow x=\sin^{-1}{\frac{1}{2}}= \frac{\pi}{6}$

Using the second derivative test,

$f''(x)=-2cosx \\ \\ \Rightarrow f''\left( \frac{\pi}{6} \right)=-2\cos{\left( \frac{\pi}{6} \right)}=-1.732$

Since the second derivative gives a negative number, the given function has a maximum point at $x=\frac{\pi}{6}$ .

And the maximum point is given by:

$f\left( \frac{\pi}{6} \right)=\frac{\pi}{6}+2\cos\left( \frac{\pi}{6} \right) \\ \\ =0.5236+2(0.8660)=0.5236+1.732 \\ \\ =\bold{2.256}$

i.e. $\left(\frac{\pi}{6},\ 2.256\right)$

Part B:

Given the function $f(x)=e^{-x}-e^{-2x}$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow-e^{-x}+2e^{-2x}=0 \\ \\ \Rightarrow2e^{-2x}=e^{-x} \\ \\ \Rightarrow2e^{-x}=1 \\ \\ \Rightarrow e^{-x}=\frac{1}{2} \\ \\ \Rightarrow-x=\ln \frac{1}{2}=-0.6931 \\ \\ \Rightarrow x=0.6931$

Using the second derivative test,

$f''(x)=e^{-x}-4e^{-2x} \\ \\ \Rightarrow f''(0.6931)=e^{-0.6931}-4e^{-2(0.6931)} \\ \\ =0.5-4e^{-1.386}=0.5-4(0.25)=0.5-1 \\ \\ =-0.5$

Since the second derivative gives a negative number, the given function has a maximum point at $x=0.6931$ .

And the maximum point is given by:

$f(0.6931)=e^{-0.6931}-e^{-2(0.6931)} \\ \\ =0.5-e^{-1.386}=0.5-0.25=\bold{0.25}$

i.e. (0.693, 0.25)

3 0

3 years ago