2(15+N)
replace a number by N
replace the sum of 15 and N by (15+N)
and lastly, replace twice by 2
So your answer is 2(15+N)
Answer:
what!!!!!!!!!!!!!!!!!! so only for dudesssssssss
Answer:
8)y=2x-3
9)y= -1/2+4
Step-by-step explanation:
9514 1404 393
Answer:
mutually exclusive
Step-by-step explanation:
The formula of interest is ...
P(A or B) = P(A) + P(B) - P(A and B)
Filling in the given values, we have ...
9/10 = 2/5 + 1/2 - P(A and B)
Solving for P(A and B), we get ...
P(A and B) = 2/5 +1/2 -9/10 = 4/10 +5/10 -9/10
P(A and B) = 0
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Events are mutually exclusive when <em>they can never happen at the same time</em>. That is, P(A and B) = 0.
The events A and B are mutually exclusive.
This question is incomplete, the complete question is;
X and Y are independent Gaussian (Normal) random Variables. X has mean 13.9 and variance 5.2; Y has mean 6.9 and variance 3.8. . (a) Calculate P( W> 10)
Answer:
P( W> 10) is 0.1587
Step-by-step explanation:
Given that;
X ⇒ N( 13.9, 5.2 )
Y ⇒ N( 6.9, 3.8 )
W = X - Y
Therefore
E(W) = E(X) - E(Y)
= 13.9 - 6.9 = 7
Var(W) = Var(X) + Var(Y) -2COV(X.Y)
[ COV(X,Y) = 0 because they are independent]
Var(W) = 5.2 + 3.8 + 0
= 9
Therefore
W ⇒ N( 7, 9 )
so
P( W > 10 )
= 1 - P( W ≤ 10 )
= 1 - P( W-7 /3 ≤ 10-7 /3 )
= 1 - P( Z ≤ 1 ) [ Z = W-7 / 3 ⇒ N(0, 1) ]
from Standard normal distribution table, P( Z ≤ 1 ) = 0.8413
so
1 - P( Z ≤ 1 ) = 1 - 0.8413 = 0.1587
Therefore P( W> 10) is 0.1587
