a >= 200
5 a + 2.5 c <=1500
Step-by-step explanation:
Step 1 :
Let c be the number of child t shirt and a be the number of adult t-shirts
Given the cost of adult t-shirt is $5 and the cost of child t-shirt is $2.50
Step 2 :
Inequality 1
Given that Jerome needs at least 200 adult t-shirts .
So the minimum quantity of adult t-shirts should be 200
Hence we have a >= 200
Step 3 :
Inequality 2
Given that the total cost should be less that $1500
We have,
5 a + 2.5 c <=1500
Answer: 3
Step-by-step explanation:
6y (1)
2 (2)
9x (3)
Answer:
33.3%
Step-by-step explanation:
The number of people that must be fed has increased from 4 to 6, so is 6/4 = 3/2 as many as planned.
Assuming the additional people eat the food at the same rate as the original people, the time and number of people are assumed to be inversely proportional. That is, the time the food will last is 2/3 of the originally expected time. It has decreased by 1/3 × 100% = 33.3%.
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If you like, you can count rations. For four people for 12 days, at 3 rations per person per day, a total of 144 rations are needed. When the number of people becomes 6, the number of days that will last is ,,,
(144 rations)/(6 persons)/(3 rations/person/day) = 8 days
The percentage change in trip days is ...
(8 -12)/12 × 100% = -4/12 × 100% = -33.3% . . . a decrease of 33.3%
I’m pretty sure it will be the last one f(x)=(3x+1)(2x-5).
