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AleksandrR [38]

3 years ago

15

A -------- of a number is that number times any whole number

1 answer:

USPshnik [31]3 years ago

5 0

Answer:

quotient

Step-by-step explanation:

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If for every 12 blue streamers there is 9 gold streamers, how many blue streamers will I have if I have 36 gold streamers?

neonofarm [45]

Answer:

You will have 48 blue streamers.

Step-by-step explanation:

This question can be solved by proportions, using rule of three.

We have that:

For 12 blue streamers, there are have 9 gold streamers. How many blue streamers are there when there are 36 gold streamers?

12 blue - 9 gold

x blue - 36 gold

Applying cross multiplication

$9x = 36*12$

Simplifying by 9

$x = 4*12 = 48$

You will have 48 blue streamers.

4 0

3 years ago

What is the value of 34 square

Oksi-84 [34.3K]

Question

What is the value of 34²

Answer:

1156

Step-by-step explanation:

just multiply 34 * 34 = 1156

5 0

3 years ago

How do you do a and b on this problem

gogolik [260]

for a all you have to do is * you will find the answer. for b what ever yo answer was for a u will put that for the hours n what u had * u put for min for seconds

8 0

3 years ago

Х- а<br>x-b<br>If f(x) = b.x-a÷b-a + a.x-b÷a - b<br>Prove that: f (a) + f(b) = f (a + b)

GenaCL600 [577]

Given:

Consider the given function:

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot(x-b)}{a-b}$

To prove:

$f(a)+f(b)=f(a+b)$

Solution:

We have,

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot (x-b)}{a-b}$

Substituting $x=a$ , we get

$f(a)=\dfrac{b\cdot(a-a)}{b-a}+\dfrac{a\cdot (a-b)}{a-b}$

$f(a)=\dfrac{b\cdot 0}{b-a}+\dfrac{a}{1}$

$f(a)=0+a$

$f(a)=a$

Substituting $x=b$ , we get

$f(b)=\dfrac{b\cdot(b-a)}{b-a}+\dfrac{a\cdot (b-b)}{a-b}$

$f(b)=\dfrac{b}{1}+\dfrac{a\cdot 0}{a-b}$

$f(b)=b+0$

$f(b)=b$

Substituting $x=a+b$ , we get

$f(a+b)=\dfrac{b\cdot(a+b-a)}{b-a}+\dfrac{a\cdot (a+b-b)}{a-b}$

$f(a+b)=\dfrac{b\cdot (b)}{b-a}+\dfrac{a\cdot (a)}{-(b-a)}$

$f(a+b)=\dfrac{b^2}{b-a}-\dfrac{a^2}{b-a}$

$f(a+b)=\dfrac{b^2-a^2}{b-a}$

Using the algebraic formula, we get

$f(a+b)=\dfrac{(b-a)(b+a)}{b-a}$ $[\because b^2-a^2=(b-a)(b+a)]$

$f(a+b)=b+a$

$f(a+b)=a+b$ [Commutative property of addition]

Now,

$LHS=f(a)+f(b)$

$LHS=a+b$

$LHS=f(a+b)$

$LHS=RHS$

Hence proved.

5 0

2 years ago

Select the correct answer.

dsp73

Answer: I believe that it is the one on the left

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers