Double check this for me please :) Did I select the correct boxes?
1 answer:
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Answer:
0.1833
Step-by-step explanation:
Given:
% of people with fibromyalgia = 2%
Probability of having a restless leg syndrome for people with fibromyalgia = 0.33
Probability of having a restless leg syndrome for people without fibromyalgia = 0.03
Take F as event of having fibromyalgia
Take R as event of having restless leg
Required:
Find the probability that a person with restless leg syndrome has fibromyalgia.
To find the probability that a person with restless leg syndrome has fibromyalgia, we have: P(F/R)
Where,
P(R/F) = 0.33
P(F) = 2% = 0.02
P(R/F') = 0.03
P(F') = 1 - 0.02 = 0.98
Therefore,
= 0.1833
Probability a person with restless leg syndrome has fibromyalgia = 0.1833
Tree diagram is attached
