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ELEN [110]
3 years ago
13

Exploring Arraylists. Remember that arraylists are good for adding and removing things, and that they are clock-cycle friendlier

in this case than resizing arrays as we discussed in lecture. This lab allows you to get some hands-on using an arraylist so you will remember it for those times it would be a good fit for an application. a) Create an Arraylist of type String and prompt the user for three names and add these names to your ArrayList. b) Print a message with the number of elements in the ArrayList for the user using the size() method (to find the number to print.) c) Prompt the user for two more names and add them to the ArrayList and once again print a message with the number of elements in the ArrayList for the user. d) Use a loop to print all of the names in the ArrayList for the user. e. Ask the user for a name to remove, remove the value the user provides, and then use a loop to print all of the names in the ArrayList for the user. (25 points)
Computers and Technology
1 answer:
Yuliya22 [10]3 years ago
5 0

Answer:

Code is given below:

Explanation:

import java.io.*;

import java.util.*;

import java.util.Scanner;

class Solution {

  public static void main(String args[]) {

      Scanner in = new Scanner(System.in);

     

     

      ArrayList<String> ans = new ArrayList();

     

      System.out.println("(a) ADD THREE NAMES: ");

     

      for(int i=0;i<3;i++)

      {

          ans.add(in.next());

         

      }

      System.out.println("(b) NUMBER OF ELEMENTS: " + ans.size());

     

      System.out.println("(c) ADD TWO MORE NAMES : ");

      for(int i=0;i<2;i++)

      {

          ans.add(in.next());

         

         

      }

      System.out.println("(d) PRINT ALL NAMES: ");

      for(int i=0;i<ans.size();i++)

      {

          System.out.println(ans.get(i));

      }

     

      System.out.println("(e) ENTER A NAME TO REMOVE: ");

      ans.remove(in.next());

      for(int i=0;i<ans.size();i++)

      {

          System.out.println(ans.get(i));

      }

     

     

  }

}

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Answer:

  1. import math  
  2. def standard_deviation(aList):
  3.    sum = 0
  4.    for x in aList:
  5.        sum += x  
  6.    
  7.    mean = sum / float(len(aList))
  8.    sumDe = 0
  9.    for x in aList:
  10.        sumDe += (x - mean) * (x - mean)
  11.    
  12.    variance = sumDe / float(len(aList))
  13.    SD = math.sqrt(variance)
  14.    return SD  
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Explanation:

The solution code is written in Python 3.

Firstly, we need to import math module (Line 1).

Next, create a function standard_deviation that takes one input parameter, which is a list (Line 3). In the function, calculate the mean for the value in the input list (Line 4-8). Next, use the mean to calculate the variance (Line 10-15). Next, use sqrt method from math module to get the square root of variance and this will result in standard deviation (Line 16). At last, return the standard deviation (Line 18).

We can test the function using a sample list (Line 20) and we shall get 4.509249752822894

If we pass an empty list, a ZeroDivisionError exception will be raised.

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