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lyudmila [28]
4 years ago
11

What is 12,000,000 in standard form

Mathematics
2 answers:
leva [86]4 years ago
6 0
It is 12 * 10^6 Hope this helps.
tresset_1 [31]4 years ago
3 0
It's actually 12,000'000
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G − 334 = –234<br><br> solve for g
Harrizon [31]

Answer: 100

Step-by-step explanation: To find g, add 334 to both sides. -234 + 334 is 100.

4 0
3 years ago
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What city is located at 39 n and 75 w
Zigmanuir [339]
I think its Philadelphia hopes this helps...
7 0
4 years ago
4. Divide, using synthetic division: 16x^3 +80x^2+x+5/x+5
fgiga [73]

Answer:

Step-by-step explanation:

x+5=0

x=-5

-5) 16   80   1    5

  |       -80   0  -5

 ____________

  | 16    0    1  | 0

quotient=16x²+1

Remainder=0

8 0
3 years ago
Can someone help me please
Misha Larkins [42]

Answer:

x= 13, angle 1= 37, and angle 2= 53

Step-by-step explanation:

So you have 2x+11+1+4x=90 degrees

If you simplify it, it becomes 6x+12=90 degrees

Then, you rearrange; 6x=90-12 or 6x= 78

So then, x=13

For angle 1 its 2x+11= 37 degrees

And angle 2 is 1+4x= 53 degrees

7 0
3 years ago
How much money has to be invested at 5.9% interest compounded continuously to have $15,000 after 12 years?
scoray [572]

The amount of $7389.43 has to be invested at 5.9% interested continuously to have $15,000 after 12 years.

Step-by-step explanation:

The given is,

                Future value, F  = $15,000

                           Interest, i = 5.9%

              ( compounded continuously )

                            Period, t = 12 years

Step:1

           Formula to calculate the present with compounded continuously,

                                       F=Pe^{(i)(t)}...............(1)

           Substitute the values in equation (1) to find the P value,

                                  15000=Pe^{(0.059)(12)}          ( ∵ i = \frac{5.9}{100}=0.059 )

                                  15000=Pe^{0.708}

                                  15000=P(2.0299)             ( ∵ e^{o.708} =2.0299 )

            We change the P (Present value) into the left side,

                                        P=\frac{15000}{2.0299}

                                            =7389.427

                                            ≅ 7389.43

                                         P = $ 7389.43

Result:

           The amount of $7389.43 has to be invested at 5.9% interested continuously to have $15,000 after 12 years.  

                       

8 0
3 years ago
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