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Sindrei [870]
3 years ago
14

The area of a rectangle is 66 ft^2 and the length of the rectangle is 7 feet less than three times the width find the dimensions

of the rectangle
Mathematics
2 answers:
Ber [7]3 years ago
4 0
<h2>Length = 11</h2><h2>Width = 6</h2>

The area of a rectangle is 66 ft^2:

L * W = 66

Length of the rectangle is 7 feet less than three times the width:

L = 3W-7

Substitute L in terms of W:

(3W-7) * W = 66

Factorise the equation:

3W^2 -7W = 66

3W^2 - 7W - 66 = 0

Factors of 66 =

1 66, 2 33, 3 22, 6 11

(3W + 11) (W - 6) = 0

Solve for W:

3W + 11 = 0

3W = 11

W = 3/11

W - 6 = 0

W = 0 + 6

W = 6

Using the original equation, find L:

L = 3W-7

L = 3(6)-7

L = 18-7

L = 11

L * W = 66

11 * 6 = 66

lyudmila [28]3 years ago
3 0

Answer:

Step-by-step explanation:

Length * width =Area

3(x-7)*x=66

x^2-7x-22=0

Solve for 'x' using quadratic formula

Now width=9.35234995ft

Length=7.05704985ft

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Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million)     Number of companies

25 up to 35                                                    4

35 up to 45                                                    19

45 up to 55                                                    27

55 up to 65                                                    16

65 up to 75                                                     9

TOTAL                                                            75

Let's find the probabilities first:

P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}

For 35 up to 45

P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}

For 45 up to 55

P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}

For 55 up to 65

P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}

For 65 up to 75

P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}

Chi-Square Table can be computed as follows:

Expense   No of   Probabilities(P)  Expe                (O-E)^2   \dfrac{(O-E)^2}{E}

             compa                                 cted E (n*p)

             nies (O)  

25-35           4      0.0612    75*0.0612 = 4.59        0.3481       0.0758

35-45           19     0.2218   75*0.2218 = 16.635     5.5932       0.3362

45-55           27     0.3568   75*0.3568 = 26.76     0.0576      0.021

55-65           16      0.2552   75*0.2552 = 19.14      9.8596      0.5151

65-75           9      0.0839     75*0.0839 = 6.2925   7.331         1.1650

                                                                                           \sum \dfrac{(O-E)^2}{E}= 2.0492                                                                                                      

Using the Chi-square formula:

X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square  \ X^2 = 2.0942

Null hypothesis:

H_o: \text{The population of advertising expenses follows a normal distribution}

Alternative hypothesis:  

H_a: \text{The population of advertising expenses does not follows a normal distribution}

Assume that:

\alpha = 0.02

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from X^2 = 11.667

Decision rule: To reject H_o  \  if \  X^2  test statistics is greater than X^2 tabulated.

Conclusion: Since X^2 = 2.0942 is less than critical value 11.667. Then we fail to reject H_o

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What is the exponential form of 175
Serggg [28]
First factor 175:

1, 5, 5, 7

Now that we know the factors of 175, combine common factors:

1, 5², 7

Hope this helps!
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Aleksandr-060686 [28]

Answer:

V = 6079.04 ft³

Step-by-step explanation:

The volume (V) of a cylinder is calculated as

V = πr²h ( r is the radius and h the height )

Here diameter = 22 , then r = 22 ÷ 2 = 11 and h = 16 , then

V = 3.14 × 11² × 16

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Find the area and the circumference of a circle with radius 7 cm.
aniked [119]

Answer:

C=14pi cm

A=49pi cm^2

Step-by-step explanation:

1) Circumference of a circle is 2piR and R=7cm

C=2pi(7)

C=14pi cm

2) Area of a circle is piR^2 and R=7cm

A=pi (7)^2

A=49pi cm^2

3 0
3 years ago
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