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Sindrei [870]
2 years ago
14

The area of a rectangle is 66 ft^2 and the length of the rectangle is 7 feet less than three times the width find the dimensions

of the rectangle
Mathematics
2 answers:
Ber [7]2 years ago
4 0
<h2>Length = 11</h2><h2>Width = 6</h2>

The area of a rectangle is 66 ft^2:

L * W = 66

Length of the rectangle is 7 feet less than three times the width:

L = 3W-7

Substitute L in terms of W:

(3W-7) * W = 66

Factorise the equation:

3W^2 -7W = 66

3W^2 - 7W - 66 = 0

Factors of 66 =

1 66, 2 33, 3 22, 6 11

(3W + 11) (W - 6) = 0

Solve for W:

3W + 11 = 0

3W = 11

W = 3/11

W - 6 = 0

W = 0 + 6

W = 6

Using the original equation, find L:

L = 3W-7

L = 3(6)-7

L = 18-7

L = 11

L * W = 66

11 * 6 = 66

lyudmila [28]2 years ago
3 0

Answer:

Step-by-step explanation:

Length * width =Area

3(x-7)*x=66

x^2-7x-22=0

Solve for 'x' using quadratic formula

Now width=9.35234995ft

Length=7.05704985ft

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Suppose the graph of y= x^2 translated left 2 units, and up 8 units
Elis [28]

Start with y = x2

 

Shift 2 units left to get y = (x+2)2

 

Vertically stretch to get y = 6(x+2)2

 

Reflect across x-axis to get y = -6(x+2)2

 

Shift 7 units down to get y = -6(x+2)2 - 7

hope this helps!

3 0
2 years ago
Three varieties of coffee long dash— Coffee​ A, Coffee​ B, and Coffee C long dash— are combined and​ roasted, yielding a 51​-lb
asambeis [7]
Let A, B and C be the number of pounds of each brand of coffee.
A+B+C=51 (weight) which is 3A+B=51 because C=2A, B=51-3A
15.99A+13.21B+19.90A=51×12.82=653.82 (cost) I’ve used C=2A
35.89A+13.21B=653.82
Substitute for B:
35.89A+13.21(51-3A)=653.82
35.89A+673.71-39.63A=653.82
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8 0
3 years ago
What is pythagoras theorem​
Alborosie

Answer:

hypotenuse²=base²x height²

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Hope it helps :)

6 0
3 years ago
What is the elapsed time between 8:00 a.m and noon ?
nikitadnepr [17]
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7 0
2 years ago
Read 2 more answers
Graham and Hunter are circus performers. A cable lifts Graham into the air at a constant speed of 1.5 ft/s. When Graham’s arms a
lidiya [134]

Answer: Hello there!

this type of equations in one dimension (when all the factors are constants) are written as:

h =  initial position +  initial velocity*t + (acceleration/2)*t^2

First, let's describe the hunter's equation:

We know that Graham moves with a velocity of 1.5 ft/s, and when he is  18 ft above the ground, Hunter throws the ball, and because Graham is pulled with a cable, he is not affected by gravity.

If we define t= 0 when Graham is 18 ft above the ground, the equation for Graham height (in feet) is:

h = 18 + 1.5t

where t in seconds.

Now, the equation for the ball:

We know that at t= 0, the ball is thrown from an initial distance of 5ft, with an initial velocity of 24ft/s and is affected by gravity acceleration g, where g is equal to: 32.2 ft/s (notice that the gravity pulls the ball downwards, so it will have a negative sign)

the equation for the ball is:

h = 5 + 24t - (32.2/2)t^2 = 5 + 24t - 16.1t^2

So the system is:

h = 18 + 1.5t

h = 5 +24t - 16.1t^2

so the right answer is A

5 0
3 years ago
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