The right answer is Option A: pq(p+1)(p-1)
Step-by-step explanation:
Given expression is
![p^3q-pq](https://tex.z-dn.net/?f=p%5E3q-pq)
Taking pq common from the expression
![pq(p^2-1)](https://tex.z-dn.net/?f=pq%28p%5E2-1%29)
We know that;
![a^2-b^2=(a+b)(a-b)](https://tex.z-dn.net/?f=a%5E2-b%5E2%3D%28a%2Bb%29%28a-b%29)
Here;
![a^2 = p^2\\b^2 = 1^2](https://tex.z-dn.net/?f=a%5E2%20%3D%20p%5E2%5C%5Cb%5E2%20%3D%201%5E2)
Therefore;
![p^2-1=(p+1)(p-1)](https://tex.z-dn.net/?f=p%5E2-1%3D%28p%2B1%29%28p-1%29)
Thus, the expression becomes
![pq(p+1)(p-1)](https://tex.z-dn.net/?f=pq%28p%2B1%29%28p-1%29)
The linear factors of
are pq(p+1)(p-1)
The right answer is Option A: pq(p+1)(p-1)
Keywords: linear factors, common terms
Learn more about linear factors at:
#LearnwithBrainly
Answer:
yltkh
Step-by-step explanation:
ewgeg
The range of a linear function can be found by evaluating the end-points, namely [-2,2] (assuming [-2,2] interval notation meaning from -2 to 2 was intended).
f(-2)=-6-12=-18
f(2)=6-12=-6
so the range of function f(x)=3x-12 for the domain [-2,2] is [-18,-6].
If the domain is actually {-2,2}, meaning only x=-2 and x=2, then the range would be {-18,-6}, i.e. exactly two points.
Answer: Angle 2: 45°
Step-by-step explanation:
All triangles add up to 180, so all you would so is take both of those angles and subtract them from 180, so basically 180 - 135
Answer:
The length of the rectangle is;
5x(x+13)/(x-5)
Step-by-step explanation:
Mathematically, we know that the area of a rectangle is the product of the length and width of the triangle
To find the length of the rectangle, we will have to divide the area by the width
we have this as;
(x^2 + 15x + 26)/6x^2 divided by (x^2-3x-10)/30x^3
thus, we have ;
(x^2 + 15x + 26)/6x^2 * 30x^3/(x^2-3x-10)
= (x^2+15x+ 26)/(x^2-3x-10) * 5x
But;
(x^2 + 15x + 26) = (x+ 2)(x+ 13)
(x^2-3x-10) = (x+2)(x-5)
Substituting the linear products in place of the trinomials, we have;
(x+2)(x+13)/(x+2)(x-5) * 5x
= 5x(x+13)/(x-5)