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4 years ago

(06.03 MC) How is the expression (3 + y) ⋅ 7 described by its factors and terms?

Mathematics

1 answer:

baherus [9]4 years ago

7 0

It has 3 factors and 2 terms

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<img src="https://tex.z-dn.net/?f=y%2B%20%20%5Cfrac%7B13%7D%7B4%7D%20%20%3D%20%28x%5E2-%20%5Cfrac%7B1%7D%7B2%7D%20%29%5E2" id="T

zhenek [66]

Answer: $\bold{y=\dfrac{1\pm \sqrt{4x+13}}{2}}$

<u>Step-by-step explanation:</u>

Inverse is when you swap the x's and y's and solve for y:

$y+\dfrac{13}{4}=\bigg(x-\dfrac{1}{2}\bigg)^2\\\\\\x+\dfrac{13}{4}=\bigg(y-\dfrac{1}{2}\bigg)^2\rightarrow \text{(swapped the x's and y's)}\\\\\\\sqrt{x+\dfrac{13}{4}}=\sqrt{\bigg(y-\dfrac{1}{2}\bigg)^2}\rightarrow \text{(took square root of both sides)}\\\\\\\sqrt{\dfrac{4x+13}{4}}=\pm \bigg(y-\dfrac{1}{2}\bigg)}\rightarrow \text{(created common denominator in radical)}\\\\\\ \dfrac{\sqrt{4x+13}}{2}=\pm \bigg(y-\dfrac{1}{2}\bigg)}\rightarrow \text{(simplified radical)}$

$\pm \dfrac{\sqrt{4x+13}}{2}=y-\dfrac{1}{2}}\rightarrow \text{(divided both sides by}\ \pm )\\\\\\\dfrac{1}{2}\pm \dfrac{\sqrt{4x+13}}{2}=y\quad \rightarrow \text{(added}\ \dfrac{1}{2}\ \text{to both sides)}\\\\\\\dfrac{1\pm \sqrt{4x+13}}{2}=y\quad \rightarrow \text{(combined numerators)}$

4 0

3 years ago

Qhat is the ratio of 6to 5

asambeis [7]

6:5 is the ratio #answerwithquality #BAL

3 0

3 years ago

1 2/3 x 3 1/2 as a mixed number in simplest form. if correct you get brainliest

olasank [31]

Answer:

Step-by-step explanation:

1 2/3 x 3 1/2 = 5

7 0

3 years ago

Solve 2 tan θ = 2 cot θ for all values of θ if θ is measured in degrees.

Nesterboy [21]

Answer:

2tanθ = 2cotθ

tanθ = cotθ

tanθ = 1 /tanθ

tan²θ = 1

tanθ = ±1

if tanθ = 1

θ = 45° + nπ (π = 180° , n is a natural number)

if tanθ = -1

θ = 135° + nπ

6 0

3 years ago

The set of ordered pairs represents a function. Write a rule that represents the function. (0,0), (1,4), (2,16), (3,36

faust18 [17]

First, we have to notice that 0 = (2*0)^2
and 4 = (2*1)^2
and 16 = (2*3)^2
and 64 = (2*4)^2
The y value is always the square of twice the x value or,
y = (2x)^2 or y = 4x^2

5 0

3 years ago