Answer:
6*x^(2/5)*y^(1/5)
Step-by-step explanation:
The fifth root of x^2 is x^(2/5).
That of y is y^(1/5).
Then the given expression, rewritten with fractional exponents, is
6*x^(2/5)*y^(1/5)
To make a neutral charge the protons and electrons need to cancel out therefore 8 electrons
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The solution of the system of linear equation are (1, 7)
<h3>How to solve system of equation?</h3>
3a + 6b = 45
2a - 2b = -12
multiply equation(ii) by 3
Therefore,
3a + 6b = 45
6a - 6b = -36
9a = 9
a = 1
Hence,
2(1) - 2b = -12
2 - 2b = -12
-2b = -12 - 2
- 2b = - 14
b = -14 / -2
b = 7
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