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solniwko [45]
3 years ago
13

During a recent sporting event, a quarter is tossed to determine which team picks the starting side. Suppose the referee says th

e coin will be tossed 3 times and the best 2 out of three wins. If team A calls ‘heads’, what is the probability that exactly 2 heads are observed in three tosses?
Mathematics
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

3/8

Step-by-step explanation:

The coin has only two possibilities: heads(H) or tails(T), so the probabilities to three tosses are:

TTT

TTH

THT

THH

HTT

HTH

HHT

HHH

So, there are 8 possibilities, and in 3 of them are exactly 2 heads. The probability is the events we want divided by the total possibles events, then it is 3/8.

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Diano4ka-milaya [45]

Answer:

30 Nickels and 188 Pennies

Step-by-step explanation:

okay, so to set up the equation first, we have to assign each coin a variable, let's call them p and n:

P= number of pennies

N= number of nickels

the value of a penny is 1 cent, so 1P, and the value of a nickel is 5 cents, so 5N

The problem states that he has 218 coins, meaning that the total number of pennies and nickels adds up to 218:

P + N = 218

the total value of the coins is $3.38, so that would mean that 1P + 5N has to equal $3.38:

1P + 5N = 338

Okay, so now that we have our equations let's solve them using elimination:

we have to get a common coefficient between both equations, so let's multiply our first equation by 5:

P x 5 = 5P

N x 5 = 5N

218 x 5 = 1090

so, now we can solve by elimination:

5P + 5N = 1090

1P + 5N = 338

the N's cancel out:

4P = 752

divide both sides by 4:

P = 188

okay, so if theres a total of 218 coins, subtract 188 from 218:

218 - 188 = 30

so, there are 30 nickels and 188 pennies.

check our work:

5 x 30 = 150

1 × 188 = 188

150 + 188 = 338

338 = 338

I hope this helps! :)

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4 years ago
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Answer:

The answer is C.

Step-by-step explanation:

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