To solve the equation below, you need to divide by what number? 98p = 197

Mathematics

2 answers:

Ilya [14]3 years ago

8 0

you need to divide by 98

98p/98=197/98

p=2.01020408 or about 2

noname [10]3 years ago

4 0

To solve the equation, you would need to divide both sides of the equation by the number 98, so that the p is by itself, and so that the equation would say something like p=_.

You might be interested in

If x= 1/2-√3 , prove that x³-2x²-7x+5=3

prohojiy [21]

$x=\frac{1}{2}-\sqrt3\\\\x^3-2x^2-7x+5=3\\\\(\frac{1}{2}-\sqrt3)^3-2(\frac{1}{2}-\sqrt3)^2-7(\frac{1}{2}-\sqrt3)+5\\\\=(\frac{1}{2})^3-3\cdot(\frac{1}{2})^2\cdto\sqrt3+3\cdot\frac{1}{2}\cdot(\sqrt3)^2-(\sqrt3)^3-...\\\\...-2[(\frac{1}{2})^2-2\cdot\frac{1}{2}\cdot\sqrt3+(\sqrt3)^2]-\frac{7}{2}+7\sqrt3+5$

$=\frac{1}{8}-\frac{3\sqrt3}{4}+\frac{9}{2}-3\sqrt3-2(\frac{1}{4}-\sqrt3+3)-\frac{7}{2}+7\sqrt3+5\\\\=\frac{1}{8}+\frac{9}{2}-\frac{1}{2}-6-\frac{7}{2}+5-\frac{3}{4}\sqrt3-3\sqrt3+2\sqrt3+7\sqrt3\\\\=\frac{1}{8}+\frac{1}{2}-1+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{1}{2}+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{4}{8}+5\frac{1}{4}\sqrt3\\\\=-\frac{3}{8}+5\frac{1}{4}\sqrt3\neq3$

6 0

3 years ago

Angle A and Angle B are Complementary Angles. If Angle A measures 40 degrees, what is the measure of Angle B? *

IceJOKER [234]

Answer:

50 degrees

Step-by-step explanation:

If angle A and angle B are complementary, that would mean that their sum is 90 degrees. A + B = 90 . We know that angle A is 40, so 40 + B = 90. It becomes a one step equation. Subtract both sides by 40. 90 - 40 = 50. Angle B is equal to 50 degrees.

6 0

3 years ago

Read 2 more answers

PLEASE ANSWERRRR

ryzh [129]

Answer:

positive

Step-by-step explanation:

If the variables tend to increase and decrease together, the association is positive.

hope this helps :)

8 0

3 years ago