(0.35x + 0.14 * 18) / y = 0.23
x + 18 = y
The 5 people can seat in a row in 5! ways
But we need to exclude the ways <span>that ann and bob are seated next to each other which is = 4! * 2!
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So, the number of <span>ways can ann, bob, chuck, don and ed be seated in a row such that ann and bob are not seated next to each other = 5! - 4! * 2! = 72
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<span>Another solution:
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<span>If ann seated in one of the ends, the number of ways = 3*2
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<span>If ann didn't seat in one of the ends , the number of ways = 2*3
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So, the total number of <span>ways that can <span>ann, bob be seated = 3*2 + 2*3 = 12
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The remaining persons can seat with a number of ways = 3! = 6
So, the total ways that the five persons can seat = 12*6 = 72
Answer:
Below.
Step-by-step explanation:
When you graph this you'll see that it is a rhombus, which has 4 equal sides and the 4 angles are not 90 degrees.
You could draw a square on the coordinate plane using A(0.0). B (0,3), C(3,3) and D(3,0). The sides of the square are all equal to the sides of the rhombus but the 2 quadrilaterals are not congruent because the angles have different values,
Answer:
The numbers are --> x = -4 + √21 i and x = -4 — √21 i
See the attachment for my step-by-step explanation
(solution is in red box)
