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inn [45]
3 years ago
13

For breakfast Bob has three options: cereal, eggs or fruit. He has to choose exactly two items out of the three available. (a) D

escribe the sample space of this experiment. Hint. What are the different possible outcomes for Bob’s breakfast? (b) Let A be the event that Bob’s breakfast includes cereal. Express A as a subset of the sample space.
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
5 0

Answer:

Step-by-step explanation:

The same space of this experiment is the possible outcomes of selecting two out of the three breakfast.  let the sample space = B

the sample space = {(cereal and egg), (cereal and fruit), (fruit and egg), (fruit and cereal), (egg and fruit), (egg and cereal)}

b) A = {(cereal and egg), (cereal and fruit), (egg and cereal), (fruit and cereal)}

A ⊆ B =n(A) ≤ n(B) (4≤6) = {(cereal and egg), (cereal and fruit), (egg and cereal), (fruit and cereal)} ⊆{(cereal and egg), (cereal and fruit), (fruit and egg), (fruit and cereal), (egg and fruit), (egg and cereal)} where a subset means all the element of A can be found in B.

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Researchers are interested if a school breakfast program leads to taller children. Assume that the population of all 5 year-old
DedPeter [7]

Answer:

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=39 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1 represent the population standard deviation

n=25 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The margin of error is given by:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

And replacing we got:

ME= 1.96 *\frac{1}{\sqrt{25}}= 0.392

Now we have everything in order to replace into formula (1):

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

7 0
3 years ago
A) y= -3.5x + 57.5<br>B) y= 3.5x + 57.5<br>C) y= -3.5x + 32.5<br>D) y= -3x + 57.5
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The answer is y=-3x+57.5
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3 years ago
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Drupady [299]

Answer:

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Step-by-step explanation:

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2 years ago
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adoni [48]

Answer:

6.517%

Step-by-step explanation:

This is a multi-year investment and we are not working with a $1 initial investment. There is no mention of compounding so we will use formula A=P0⋅(1+r)N with A=$18,434 and P0=$14,320. We do not know the value of r. However, N=4 years. Substituting the values we have $18,434=$14,320⋅(1+r)4. Divide both sides of the equation by $14,320. Next, take the fourth root of both sides of the equation and subtract 1 to find the decimal form of r.

$18,4341.287291.065170.06517=$14,320⋅(1+r)4=(1+r)4=1+r=r

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6 0
3 years ago
Please help with the this give tiny explanation
Mila [183]

Answer:

21

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