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3 years ago

Show your work please

Mathematics

1 answer:

natali 33 [55]3 years ago

5 0

Answer:

Step-by-step explanation:

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Rita and Tina each make $11 an hour working as cashiers at a supermarket. Last week, Rita worked r hours while Tina worked t hou

Hoochie [10]

Answer: Rita and Tina's total weekly wages can be represented as 11r + 32 + 11t or 11( r + t ) + 32

Step-by-step explanation:

Since, For Rita,

Charges per hour = $ 11

Working time = r hours,

Overtime charges for a week = $ 32,

Thus, her weekly charges = 11 r + 32

Now, For Tina,

Charges per hour = $ 11

Working time = t hours,

Thus, her weekly charges = 11 t

Hence, the combined weekly wages of both Rita and Tina = 11 r + 32 + 11 t

= 11( r + t ) + 32

Which is the required expression.

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3 years ago

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Find the y-intercept of f(x)=2x^2-2x+1

Y_Kistochka [10]

Answer:

Step-by-step explanation:

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3 years ago

How many half-lives of radon-222 have passed in 11.46 days? If 5.2 × 10−8 g of radon-222 remain in a sealed box after 11.46 days

Svetach [21]

Answer:

(i) Approximately 3 half lifes

(ii) $4.21\times 10^{-7}\text{ g}$

Step-by-step explanation:

(i) ∵ The half life of Radon-222 is approximately 3.8 days,

So, the number of half life in 11.46 days = $\frac{11.46}{3.8}$ ≈ 3

(ii) Since, the half life formula is,

$N=N_0 (\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}$

Where,

$N_0$ = initial quantity,

t = number of periods

$t_{\frac{1}{2}}$ = half life of the quantity,

Given,

N = $5.2\times 10^{-8}\text{ g}$

t = 11.46 days,

$t_{\frac{1}{2}} = 3.8\text{ days}$

$\implies 5.2\times 10^{-8}=N_0 (\frac{1}{2})^\frac{11.46}{3.8}$

$\implies N_0=2^{\frac{11.46}{3.8}}\times 5.2\times 10^{-8}\approx 4.21\times 10^{-7}\text{ g}$

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4 years ago

Which graph corresponds to the following inequality? A. B. C. D.

zlopas [31]

I can see the question but if you add a picture maybe i’ll understand it a little more

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2 years ago

Which of the following is a correct cosine ratio for the figure?

LenKa [72]

B! cosine is adjacent over hypotenuse

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