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3 years ago

Which graph shows the solution to the inequality -3x-7 <20?

Mathematics

1 answer:

ki77a [65]3 years ago

4 0

Answer:

x > -9

Step-by-step explanation:

The solution to the inequality is obtained as follows:

-3x -7 < 20

-3x - 7 + 7 < 20 + 7

-3x < 27

-3x/(-3) > 27/(-3)

x > -9

Notice that when you divide by a negative number, the inequality sign changes.

In the picture attached, the graph of the solution s shown. Notice that -9 is not included in the solution.

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Help ASAP 40 Points and Brainliest

Mandarinka [93]

Answer:

Volume of a cup

The shape of the cup is a cylinder. The volume of a cylinder is:

\text{Volume of a cylinder}=\pi \times (radius)^2\times heightVolume of a cylinder=π×(radius)

×height

The diameter fo the cup is half the diameter: 2in/2 = 1in.

Substitute radius = 1 in, and height = 4 in in the formula for the volume of a cylinder:

\text{Volume of the cup}=\pi \times (1in)^2\times 4in\approx 12.57in^3Volume of the cup=π×(1in)

×4in≈12.57in

2. Volume of the sink:

The volume of the sink is 1072in³ (note the units is in³ and not in).

3. Divide the volume of the sink by the volume of the cup.

This gives the number of cups that contain a volume equal to the volume of the sink:

\dfrac{1072in^3}{12.57in^3}=85.3cups\approx 85cups

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Answer:

Step-by-step explanation:

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Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
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Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

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$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

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Which graph shows the solution to the inequality -3x-7 <20?​

Which graph shows the solution to the inequality -3x-7 <20?