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WINSTONCH [101]
3 years ago
12

Sound is a form of _______.

Advanced Placement (AP)
2 answers:
Bogdan [553]3 years ago
5 0

Sound is a form of energy, just like electricity and light. A sound is made when air molecules vibrate and move in a pattern called waves, or sound waves.

UNO [17]3 years ago
5 0

Answer:

the correct answer is energy

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The pegboard system can be described as?
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A recording system using a pegboard to increase daily productivity with transactions; also referred to a one-write system.
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All of the following should be included on the self stick labels you prepare before attending a college fair except
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2 years ago
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Stock Y has a beta of 1.0 and an expected return of 12.4 percent. Stock Z has a beta of .6 and an expected return of 8.2 percent
Harlamova29_29 [7]

Answer: 1.9%

Explanation:

First derive the Market return as this is needed in the Capital Asset Pricing Model by using the same model:

Required return = Risk free rate + Beta * ( market return - Risk free rate)

Using stock Y:

12.4% = Risk free rate + 1 * (market return - Risk free rate)

12.4% = Rf + market return - Rf

Market return = 12.4%

Use this to calculate the Risk free rate:

Stock Z:

8.2% = Rf + 0.6 * (12.4% - Rf)

8.2% = Rf + 7.44% - 0.6Rf

Rf - 0.6Rf = 8.2% - 7.44%

0.4Rf = 0.76%

Rf = 0.76% / 0.4

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7 0
2 years ago
Limit as x approaches 0 of (2e^x-2)/x
Snowcat [4.5K]

Answer:

Explanation:

\lim_{x \to \ 0} \frac{2e^x-2}{x}

So first, we have to plug in zero and see if we can evaluate this limit simply from that.

When we plug in zero we get: (2e^0-2)/0

e^0 is 1 so we have 2-2/0 or 0/0. So we have an indeterminate form type 0/0.

This means we have to apply L'Hospital's Rule.

As a reminder L'Hospitals Rule is \lim_{x\to \ c} \frac{f'(x)}{g'(x)}

Meaning that we take the derivative of the top and bottom function as the approach some value "c". We can do this with a 0/0 indeterminate form.

So:

The derivative of 2e^x - 2 is just 2e^x

and the derivative of x is 1

So we are left with \lim_{x \to \ 0} 2e^x

Plugging in zero we see this gives us 2 as 2(e^0) = 2(1) = 2.

Hence, \lim_{x \to \ 0} \frac{2e^x-2}{x} = 2

3 0
3 years ago
Hello, I need help with this, thank you
ch4aika [34]
I would say A would the best possible answer
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