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2 years ago

Write this decimal in a fraction in its simplest form.

Mathematics

1 answer:

sammy [17]2 years ago

5 0

The simplified form of that decimal in fraction form is 3/20. Hope this helps.

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Simplify fully<br> A) <br> X^7 / X^3 <br><br><br> B)<br> Y^5 / Y^4

DENIUS [597]

Hi,

$\frac{x^{a} }{x^{b} } =x^{a-b}$

$\frac{x^{7} }{x^{3} }= x^{7-3} = x^{4}$

$\frac{y^{5} }{y^{4} } = y^{5-4} = y^{1} = y$

;)

8 0

1 year ago

This is a little hard i guess so i added a little more points :D math btw

Sonbull [250]

Answer:

First,I will add all the numbers up which is 4+5+6+9=24.Then,i would find the total amount of people which is 4.Then you divide it by 4 and you get 6.And there is your answer.Each person get 6 marble.

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

EASY BRAINLIEST PLEASE HELP!!

butalik [34]

Answer:

see below

Step-by-step explanation:

<h3>Proposition:</h3>

Let the diagonals AC and BD of the Parallelogram ABCD intercept at E. It is required to prove AE=CE and DE=BE

<h3>Proof:</h3>

1)The lines AD and BC are parallel and AC their transversal therefore,

$\displaystyle \angle DAC = \angle ACB \\ \ \qquad [\text{ alternate angles theorem}]$

2)The lines AB and DC are parallel and BD their transversal therefore,

$\displaystyle \angle BD C= \angle ABD \\ \ \qquad [\text{ alternate angles theorem}]$

3)now in triangle ∆AEB and ∆CED

$\displaystyle \angle EAD=\angle ECB$
$\angle EDA=\angle EBC$
$\displaystyle AD=BC$

therefore,

$\displaystyle \Delta AEB \cong \Delta CED$

hence,

AE=CE
DE=BE

Proven

6 0

2 years ago

Someone please help me with this

goldfiish [28.3K]

Answer:

<em>50° is the correct answer</em>

Step-by-step explanation:

<u>Right Triangles</u>

The right triangles are identified because they have an internal angle of 90°. The basic trigonometric ratios can be used to find angles and side lengths as needed.

We have a right triangle with the following characteristics:

The hypotenuse is 13 units long

The indicated angle is opposite to the leg of 10 units long.

When we know the length of the opposite side, we use the sine ratio. Let's call θ to the required angle:

$\displaystyle \sin\theta=\frac{\text{opposite side}}{\text{hypotenuse}}$