She planted 7 zucchini, 14 cucumbers, and 22 tomatoes.
Let z = the number of zucchini planted. Since she planted twice as many cucumbers as zucchini, 2z is the number of cucumbers. She planted 8 more tomatoes than cucumbers, so 2z + 8 is the number of tomatoes. This gives us the equation
z + 2z + 2z + 8 = 43
Combining like terms, we have
5z + 8 = 43
Subtract 8 from each side:
5z + 8 - 8 = 43 - 8
5z = 35
Divide both sides by 5:
5z/5 = 35/5
z = 7
There were 7 zuccchini; 2*7 = 14 cucumbers; and 14+8=22 tomatoes.
Answer:
Step-by-step explanation:
Given: r(x)=3x-1 and s(x)= 2x+1
We have to find
That is to find
first find r (6) and s(6) , then substitute, we get,
r(6)
r(x) = 3x - 1
Put x = 6 , we get
r(6) = 3(6) -1 = 18 - 1 = 17
s(6)
s(x) = 2x + 1
Put x = 6 , we get
s(6) = 2(6) + 1 = 12 + 1 = 13
Thus,
Answer:
7 & 8
Step-by-step explanation:
they are one integer apart, and if you add the two up, it makes 15
Hope this helps!
<span>let 'x' be the amount for cat's food and medication
'y' be the amount for dog's food and medication.
since the cost of food and medication for a cat is $5 less than two-thirds of the cost of food and medication for a dog then you'll have the equation as:
x = 2/3y - 5 ------equation 1
knowing that the total is 195 and there are 6 cats and a dog then,
6x + y = 195 -----equation 2
substitute equation 1 to equation 2
6x + y = 195
6(2/3y - 5) + y = 195
distribute 6 to the quantity
4y - 30 + y = 195
4y + y = 195 + 30
5y = 225
y = $45</span>
12,870 dollars. Let me know if you want me to show my work.