. x + (x + 2)≤166
. 2x+2≤166
. x≤83 - 1
. x≤82
. x=81
. 81+(81+2)=164; 164<166
answer: 81 and 83
Auditing, fraud examination, and cybersecurity
<span>f(x) = x^2 + 1, find f(a + 1)
so
</span> f(a + 1) = (a+1)^2 +1
f(a + 1) = a^2 + 2a + 1 + 1
f(a + 1) = a^2 + 2a + 2
