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3 years ago

Please help me and show work

Mathematics

2 answers:

Andrews [41]3 years ago

4 0

1. is irrational
2. = 5.65
3. = 7 7*7=49
4. = 9. 9*9=81
That's my work if you need more then I'm sorry hope this helped!

Harrizon [31]3 years ago

3 0

He square root of 30...........

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Help i cant figure this out:(

stealth61 [152]

Answer:

6-2=4

31/5 x 8 = 248/40

15/8 x 5 = 75/40

248-75=173

4 13/40

answers in order

6-2=4

6 1/5 - 1 7/8 = 4 13/40

Hope this helps

Step-by-step explanation:

8 0

3 years ago

Use green’s theorem to evaluate

Georgia [21]

By Green's theorem (all the conditions are met), we have

$\displaystyle \int_C \sqrt y \, dx + \sqrt x \, dy = \iint_D \frac{\partial(\sqrt x)}{\partial x} - \frac{\partial(\sqrt y)}{\partial y} \, dx \, dy$

where D is the interior of the path C, or the set

$D = \left\{ (x, y) : 0 \le y \le \dfrac{x^2}2 \text{ and } 0 \le x \le 2 \right\}$

So, the line integral reduces to the double integral,

$\displaystyle \frac12 \int_0^2 \int_0^{\frac{x^2}2} x^{-\frac12} - y^{-\frac12} \, dy \, dx$

$\displaystyle = \frac12 \int_0^2 x^{-\frac12}\left(\frac{x^2}2\right) - 2\left(\frac{x^2}2\right)^{\frac12} \, dx$

$\displaystyle = \frac12 \int_0^2 \frac12 x^{\frac32} - \sqrt 2 \, x \, dx$

$\displaystyle = \frac14 \int_0^2 x^{\frac32} - 2\sqrt 2 \, x \, dx$

$\displaystyle = \frac14 \left(\frac25\cdot2^{\frac52} - \sqrt2\cdot2^2\right) = \boxed{-\frac{3\sqrt2}5}$

5 0

2 years ago

3x+2y-5z=-1<br> 4x-3y+2z=-13<br> 2x-5y+4z=-9

Lina20 [59]

34252

I just guessed but here

5 0

3 years ago

What is A rectangle of sides 6cm and 4 cm <br>plzz hurry

vladimir1956 [14]

Answer:

24cm^2

Step-by-step explanation:

Given data

Length= 6cm

Width=4cm

Required

The area of the Rectangle

Area=Length*Width

Substtiute

Area=6*4

Area= 24cm^2

5 0

3 years ago

Least to greatest -3, 3 1⁄3, -3 3⁄4, 3 1⁄10

stiv31 [10]

Answer:

-3 3/4, -3, 3 1/10, 3 1/3

Step-by-step explanation:

in negative numbers bigger number is always smaller in value and in fractions bigger numbers yet again if in a small portion is a smaller value

5 0

4 years ago