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zavuch27 [327]
3 years ago
12

Evaluate the infinite sum

Mathematics
2 answers:
mote1985 [20]3 years ago
8 0

Answer:

It does not converge.

Step-by-step explanation:

Given is an infinite geometric series whose first term is a = 4/7 and common ratio is r = 7/6.

The series ∑a·rⁿ converges if we have |r| < 1.

And the series ∑a·rⁿ diverges if we have |r| > 1.

But we can easily check that |r| = 7/6 > 1.

It means the given series diverges, i.e. does not converge.

Hence, option D is correct answer, i.e. It does not converge.

Effectus [21]3 years ago
6 0

The sum does not converge because \dfrac76>1.

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A marketing company had a profit of 5625.14 in January a loss of 4250.35. In February and a profit of 1475.55 in March did the c
timofeeve [1]
Jan. profit.....    5625.14
feb..loss...     - 4250.35
march..profit...1475.55

add the profits and subtract the losses...if the result is positive, then the company made a profit....if the result is negative, then the company had a loss.

(5625.14 + 1475.55) - 4250.35 = 7100.69 - 4250.35 = 2850.34.....as u can see, the result ended in a positive number....so, in the 3 month period, the company made a profit of $ 2850.34 <==
5 0
3 years ago
Drag and drop numbers into the boxes so that the paired values are in a proportional relationship.
mezya [45]

Answer:

A=6 and B=4.5

Step-by-step explanation:

You are given table

\begin{array}{cccccc}x&2&4&[A]&7&9\\y&1&2&3&3.5&[B]\end{array}

If the paired values are in a proportional relationship, then

\dfrac{2}{1}=\dfrac{4}{2}=\dfrac{[A]}{3}=\dfrac{7}{3.5}=\dfrac{9}{[B]}.

Note that

\dfrac{2}{1}=\dfrac{4}{2}=\dfrac{7}{3.5}=2,

then

\dfrac{[A]}{3}=2\Rightarrow [A]=6,\\ \\\dfrac{9}{[B]}=2\Rightarrow [B]=\dfrac{9}{2}=4.5.

4 0
3 years ago
Which fraction has a value that's equal to 7⁄8?
Katen [24]
B is the answer to the question
3 0
2 years ago
Does anyone know the answer?
BaLLatris [955]

Answer: (11/2)π units.

Step-by-step explanation:

I've attached the solution.

Before seeing it there is a theorem you should remember.

The angle subtended by an arc of a circle at its center is twice of the angle it subtends anywhere on the circle’s circumference.

4 0
3 years ago
Which is the simplified from of p0
tiny-mole [99]
For this case we have the following expression:
p ^ 0
By properties of exponents we have:
Any number raised to the exponent zero is equal to one.
We have then, that applying this property:
p ^ 0 = 1
Answer:
the simplified form of p ^ 0 is:
D. 1
3 0
3 years ago
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