Answer:
(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Step-by-step explanation:
Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.
(a)
Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b)
A sample of <em>n</em> = 246 is selected.
Compute the probability that a sample mean is between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Answer:
f(3) = -11
Step-by-step explanation:
f(x) = -3x-2
let x=3 and replace it in the above equation
f(3) = -3(3) -2
f(3) = -9 -2
f(3) = -11
Answer:
25 centimeters
Step-by-step explanation:
1 meter is 100 centimeters.
10 ÷ 4 = 25
The distributive property: a(b + c) = ab + ac
12(6k + 3) + 4(7 - 5k) = 12(6k) + 12(3) + 4(7) + 4(-5k)
= 72k + 36 + 28 - 20k = 52k + 64
Answer:
Since the -5 is a bigger number than 1 you would keep the negative and carry it to the -4.
Step-by-step explanation: