1500*2%=30
30*4=120
1500+120+1720
1720 deer in 4 years
The inequality statement shows that both Jose and Sue landed on red or blue squares and hence both lost some points. The points they lost were more than the points they gained, which resulted in an overall score having a negative value for each player.
Jose had a final score of -2 and Sue had a final score of -5. This means, Sue scored less and probably lost more points as compared to Jose. There is a difference of 3 points between the scores of both players.
D = 900t
because if you want to simplify t (2 hours) into one then you divide 1800 by 2 and that gives you the constant of proportionality (slope) of 900. Using this information you can write the expression d = 900t.
A suitable probability app shows the 1st percentile to be at about 11040 pages.
_____
The app shown has an error in the first decimal digit. The number is closer to 11040.82301. We expect the manufacturer would round to the nearest 10 or 50 or 100 in advertising.
Answer:
a) The Venn diagram is presented in the attached image to this answer.
b) 0.82
c) 0.16
Step-by-step explanation:
a) The Venn diagram is presented in the attached image to this answer.
n(U) = 100%
n(S) = 48%
n(B) = 66%
n(H) = 38%
n(S n B) = 30%
n(B n H) = 22%
n(S n H) = 28%
n(S n B n H) = 12%
The specific breakdowns for each subgroup is calculated on the Venn diagram attached.
b) The probability that a randomly selected student likes basketball or hockey.
P(B U H)
From the Venn diagram,
n(B U H) = n(S' n B n H') + n(S' n B n H) + n(S n B n H') + n(S n B n H) + n(S n B' n H) + n(S' n B' n H) = 26 + 10 + 18 + 12 + 16 + 0 = 82%
P(B U H) = 82/100 = 0.82
c) The probability that a randomly selected student does not like any of these sports.
P(S' n B' n H')
n(S' n B' n H') = n(U) - [n(S' n B n H') + n(S' n B n H) + n(S n B n H') + n(S n B n H) + n(S n B' n H) + n(S' n B' n H) + n(S n B' n H')]
n(S' n B' n H') = 100 - (26 + 10 + 18 + 12 + 16 + 0 + 2) = 100 - 84 = 16%
P(S' n B' n H') = 16/100 = 0.16