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Stolb23 [73]
3 years ago
15

A baseball is thrown upwards from a height of 5 feet with an initial speed of 64 feet per second, and its height h (in feet) fro

m the ground is given by h(t) = 5 + 64t – 16t2 where t is time in seconds. Using a graphing calculator, determine at what time the ball reaches its maximum height. 0 seconds 1 second 2 seconds 3 seconds
Mathematics
2 answers:
allochka39001 [22]3 years ago
8 0

Answer:

C. <em><u>2sec</u></em>

....................

Bingel [31]3 years ago
3 0
Maximum can be determined by taking derivative and set it equal to zero. 

\frac{d}{dx}(5+64t-16t^2) = 64 - 32t&#10;&#10;64-32t=0&#10;&#10;32t=64&#10;&#10;t=2


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suppose you plan to ride your bicycle from portland oregon to seattle washington and back to portland. the distance between port
grin007 [14]

Answer:

d(x) = 175 - |175 - 25x|

Step-by-step explanation:

Suppose I plan to ride your bicycle from Portland Oregon to Seattle Washington and back to Portland.

Portland and Seattle are 175 miles apart. I plan to travel 25 miles every day.

If we consider the starting point i.e. Portland as the zero distance i.e. reference, then we can model the distance from Portland d(x) as

d(x) = 175 - |175 - 25x|

where x is the number of days into the ride. (Answer)

7 0
3 years ago
A county is considering rasing the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 m
DochEvi [55]

Answer:

No, at alpha equals 0.10​, we do not have enough evidence to support the​ county's claim.

Step-by-step explanation:

We are given that a county is considering raising the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 miles per hour.

A random sample of 15 vehicles has a mean speed of 31 miles per hour and a standard deviation of 4.7 miles per hour.

<em><u>Let </u></em>\mu<em><u> = true mean speed of the vehicles.</u></em>

SO, <u>Null Hypothesis</u>, H_0 : \mu \leq  30 miles per hour   {means that the mean speed of vehicles is lesser than or equal to 30 miles per hour}

<u>Alternate Hypothesis,</u> H_A : \mu > 30 miles per hour   {means that the mean speed of vehicles is greater than 30 miles per hour}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean speed of 15 vehicles = 31 mph

             s = sample standard deviation = 4.7 mph

             n = sample of vehicles = 15

So, <em><u>test statistics</u></em>  =   \frac{31-30}{\frac{4.7}{\sqrt{15} } }  ~ t_1_4

                               =  0.824

<u><em>Hence, the value of test statistics is 0.824.</em></u>

<em />

<em>Now at 0.10 significance level, the t table gives critical value of 1.345 at 14 degree of freedom for right-tailed test. Since our test statistics is less than the critical value of t as 0.824 < 1.345, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.</em>

<em />

Therefore, we conclude that the mean speed of vehicles is lesser than or equal to 30 miles per hour which means that the county's claim is not supported.

4 0
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The answer to question 1 is 25\12
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I attached your answer below...

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