A baseball is thrown upwards from a height of 5 feet with an initial speed of 64 feet per second, and its height h (in feet) fro

Question

3 years ago

15

A baseball is thrown upwards from a height of 5 feet with an initial speed of 64 feet per second, and its height h (in feet) fro

m the ground is given by h(t) = 5 + 64t – 16t2 where t is time in seconds. Using a graphing calculator, determine at what time the ball reaches its maximum height. 0 seconds 1 second 2 seconds 3 seconds

Mathematics

2 answers:

allochka39001 [22] · Answer 1 · 2022-03-11T16:24:43+03:00

allochka39001 [22]3 years ago

8 0

Answer:

C. <em><u>2sec</u></em>

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Bingel [31] · Answer 2 · 2022-03-11T14:00:38+03:00

Bingel [31]3 years ago

3 0

Maximum can be determined by taking derivative and set it equal to zero.

$\frac{d}{dx}(5+64t-16t^2) = 64 - 32t

64-32t=0

32t=64

t=2$