Question

Solve the system of equations by graphing B2%7Dx%2B2%20%7D%20%5Catop%20%7By%3D3x-7%7D%7D%20%5Cright." id="TexFormula1" title=" \left \{ {{y=- \frac{3}{2}x+2 } \atop {y=3x-7}} \right." alt=" \left \{ {{y=- \frac{3}{2}x+2 } \atop {y=3x-7}} \right." align="absmiddle" class="latex-formula"> *Show all work

Answer 1

1) Graph of y = - (3/2)x + 2

That is a straightline with slope -3/2 and y-intercept  2

If you do not know how to graph it, you can make a table like this:

x             y = (-3/2)x + 2

-1            3/2 + 2 = 7/2

0              0 + 2 = 2

2              - 3 + 2 = -1

4              - 6 + 2 = - 4

2) Graph of y = 3x - 7

That is a straight line with slope 3 and y intercept  -7

If you do not know how to graph it you can make a table like this:

x         y = 3x - 7

-1         - 3 - 7 = - 10

0          0 - 7 = - 7

1          3 - 7 = - 4

2          6 - 7 = - 1

3         9 - 7 = 2

3) When you draw the two lines you will see that the intersect at x = 2, with the correspondant y = - 1.

That point of intercection is the solutions of the system (2, -1)