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3 years ago

5

You have been advised to save 5% of your income for an emergency fund. How much would you have saved in one year, following the

recommended 5%, if you have an after tax income of $48,948.

1 answer:

Inessa [10]3 years ago

6 0

You would save $2447.40 for the emergency fund

You might be interested in

Find the difference between the actual values of the two sixes in the number 6036

aleksley [76]

The difference between the two sixes is the first six’s actual value is 6000 where the second six is 6

5 0

3 years ago

COOKING Franklin is cooking a 3-pound turkey breast for 6 people. If the number of pounds of turkey varies directly with the num

Gwar [14]

<u>Answer-</u>

2, 4, and 8 people will need 1, 2, 4 pounds of turkey respectively.

<u>Solution-</u>

Given in the question, number of pounds of turkey varies directly with the number of people, i.e as the number of people increases or decreases, the pound of turkey also increases or decreases.

Taking,

x = number of people,

y = pounds of turkey.

This condition can be represented as,

$\Rightarrow y\ \alpha \ x\\\Rightarrow y=kx$

As given in the question, when x = 6 y = 3

$\Rightarrow 3=k\times 6$

$\Rightarrow k=\frac{3}{6}= \frac{1}{2}$

Now, putting the values of k in the equation, the equation becomes

$\Rightarrow y=\frac{1}{2}x$

Now, we can get the values of y or number of pounds of turkey needed by putting the given x or number of people.

All the calculations are shown in the attached table.

5 0

3 years ago

Soo I need help... can u help?

Luda [366]

Answer:

I think its (6042 = 1780 + a) but I'm not really sure though but I hope if that helped somehow

6 0

3 years ago

Read 2 more answers

Find four distinct complex numbers (which are neither purely imaginary nor purely real) such that each has an absolute value of

Luda [366]

Answer:

0.5 + 2.985i
1 + 2.828i
1.5 + 2.598i
2 + 2.236i

Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

$|C| = \sqrt{a^2+b^2}$

Then, the work consists in finding pairs (a,b) for which:

$\sqrt{a^2+b^2}=3$

You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

$\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}$

I will use b =0.5, b = 1, b = 1.5, b = 2

$b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236$

Then, four distinct complex numbers that have an absolute value of 3 are:

0.5 + 2.985i
1 + 2.828i
1.5 + 2.598i
2 + 2.236i

4 0

4 years ago

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

7 0

3 years ago